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patriot [66]
3 years ago
7

Need help dhdudhehebdhdbdhdbdhbdbdbshsshhshsshhshsshhshs

Mathematics
1 answer:
Anna007 [38]3 years ago
8 0
X is 12 your welcome pls make me brainliest answer
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A line passes through (-2,3), (2,5), and (6,k). Find k.
Semenov [28]
We know the line runs through -2,3 and 2,5.

it also runs through 2, 5 and 6,k.

since all points are on the line, they're colinear, and therefore the line runs also through -2,3 and 6,k.

keeping in mind that line maintains a constant slope, therefore, the slope for -2,3 and 2,5, has to be the same slope as for 2,5 and 6,k.

what is the slope of -2,3  and 2,5 anyway?

\bf \begin{array}{ccccccccc}
&&x_1&&y_1&&x_2&&y_2\\
%  (a,b)
&&(~{{ -2}} &,&{{ 3}}~) 
%  (c,d)
&&(~{{ 2}} &,&{{ 5}}~)
\end{array}
\\\\\\
% slope  = m
slope = {{ m}}\implies 
\cfrac{\stackrel{rise}{{{ y_2}}-{{ y_1}}}}{\stackrel{run}{{{ x_2}}-{{ x_1}}}}\implies \cfrac{5-3}{2-(-2)}\implies \cfrac{5-3}{2+2}\implies \cfrac{2}{4}\implies \cfrac{1}{2}

and since we know the slope of 2,5 and 6,k is the same, then,

\bf \begin{array}{ccccccccc}
&&x_1&&y_1&&x_2&&y_2\\
%  (a,b)
&&(~{{ 2}} &,&{{ 5}}~) 
%  (c,d)
&&(~{{ 6}} &,&{{ k}}~)
\end{array}
\\\\\\
% slope  = m
slope = {{ m}}\implies 
\cfrac{\stackrel{rise}{{{ y_2}}-{{ y_1}}}}{\stackrel{run}{{{ x_2}}-{{ x_1}}}}\implies \cfrac{k-5}{6-2}\implies \cfrac{k-5}{4}=\stackrel{slope}{\cfrac{1}{2}}
\\\\\\
2k-10=4\implies 2k=14\implies k=\cfrac{14}{2}\implies k=7
4 0
3 years ago
59.00 m – 26.00 cm =
Whitepunk [10]

Answer:

58.74 meters

hope this helps :)

5 0
4 years ago
The center of a hyperbola is (−2,4) , and one vertex is (−2,7) . The slope of one of the asymptotes is 1/2 .
Lunna [17]

The equation of the hyperbola in standard form is (y^2 / 49) - (x^2 / 4) = 1.

<u>Step-by-step explanation:</u>

  1. Hyperbola is a section of the cone formed by intersecting a right circular cone with a plane at an angle where both halves of the cone are intersected.
  2. The vertex and the center of the hyperbola are present both on the same line x = -2. (i.e. on the y-axis), hence the branches of the hyperbola are above and below each other. The slope of the asymptotes is +(or)- a/b.

Here the vertex is 7 units so a = 7 and a^2 = 49.

Slope of the asymptotes = a/b = 1/2.

Here b = 2 and b^2 = 4.

The standard equation of the hyperbola is,

                                  (y^2 / 49) - (x^2 / 4) = 1.

4 0
3 years ago
HELP SOON!!<br> What is sum of the geometric series 5 sigma k-1 6(4)^4-1?<br> (picture attached)
Rama09 [41]

Answer:

the answer is 2,046...

7 0
3 years ago
Read 2 more answers
A half-marathon is 13.1 miles long.
N76 [4]

Answer:

144.1

Step-by-step explanation:

6 0
4 years ago
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