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tangare [24]
3 years ago
14

The quotient of (x5 – 3x3 – 3x2 – 10x 15) and (x2 – 5) is a polynomial. what is the quotient? x5 – 3x3 – 2x2 – 10x 10 x7 – 8x5 –

3x4 5x3 30x2 50x – 75 x3 2x – 3 x5 – 3x3 – 4x2 – 10x 20
Mathematics
1 answer:
Lina20 [59]3 years ago
3 0

The quotient of (x^5 – 3x^3 – 3x^2 – 10x + 15) and (x^2 – 5) is a  (x^5-3x -3 - 24x/(x²-5)) polynomial.

<h3>What are the Quotients?</h3>

Quotients are the number that is obtained by dividing one number by another number.

The quotient of (x^5 – 3x^3 – 3x^2 – 10x + 15) and (x^2 – 5) is a polynomial.

(x^5 - 3x³ - 3x² - 10x + 15) / p = x² - 5

p = (x^5 -3x³ - 3x² - 10x + 15)/(x² - 5)

= x^5 -3x - 3 - 24x/(x² - 5)

x^5 3x³ + 15x

x^5 - 3x² - 24x + 15

x^5 - 3x² + 15

0 - 24x + 0

Learn more about quotient ;

brainly.com/question/1498111

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3 years ago
Samantha has 23 strawberries and wants to put 4 strawberries into each bowl. How many bowls can Samantha put exactly 4 strawberr
Bogdan [553]

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Edit: It should be 5 bowls because if she wants to put an equal amount of strawberries into her bowls it should be 5.

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8 0
3 years ago
What is the probability that a random person who tests positive for a certain blood disease actually has the disease, if we know
xeze [42]

Answer:

Step-by-step explanation:

Hello!

Any medical test used to detect certain sicknesses have several probabilities associated with their results.

Positive (test is +) ⇒ P(+)

True positive (test is + and the patient is sick) ⇒ P(+ ∩ S)

False-positive (test is + but the patient is healthy) ⇒P(+ ∩ H)

Negative (test is -) ⇒ P(-)

True negative (test is - and the patient is healthy) ⇒ P(- ∩ H)

False-negative (test is - but the patient is sick) ⇒ P(- ∩ S)

The sensibility of the test is defined as the capacity of the test to detect the sickness in sick patients (true  positive rate).

⇒ P(+/S) =<u> P(+ ∩ S)  </u>

                    P(S)

The specificity of the test is the capacity of the test to have a negative result when the patients are truly  healthy (true negative rate)

⇒ P(-/H) =<u> P(- ∩ H)  </u>

                   P(H)

For this particular blood disease the following probabilities are known:

1% of the population has the disease: P(S)= 0.01

95% of those who are sick, test positive for it: P(+/S)= 0.95 (sensibility of the test)

2% of those who don't have the disease, test positive for it: P(+/H)= 0.02

The probability of a person having the blood sickness given that the test was positive is:

P(S/+)= <u> P(+ ∩ S)  </u>

                P(+)

The first step you need to calculate the intersection between both events + and S, for that you will use the information about the sickness prevalence in the population and the sensibility of the test:

P(+/S) =<u> P(+ ∩ S) </u>

                 P(S)

P(+/S)* P(S)  = P(+ ∩ S)  

P(+ ∩ S) = 0.95*0.01= 0.0095

The second step is to calculate the probability of the test being positive:

P(+)=  P(+ ∩ S) +  P(+ ∩ H)

Now we know that 1% of the population has the blood sickness, wich means that 99% of the population doesn't have it, symbolically: P(H)= 0.99

Then you can clear the value of P(+ ∩ H):

P(+/H) =<u> P(+ ∩ H) </u>

                 P(H)

P(+/H)*P(H)  = P(+ ∩ H)

P(+ ∩ H) = 0.02*0.99= 0.0198

Next you can calculate P(+):

P(+)=  P(+ ∩ S) +  P(+ ∩ H)= 0.0095 + 0.0198= 0.0293

Now you can calculate the asked probability:

P(S/+)= <u> P(+ ∩ S)  </u> =<u> 0.0095 </u>= 0.32

                P(+)        0.0293

I hope it helps!

                 

                 

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