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malfutka [58]
3 years ago
10

Principal=2000,R=12percent,Time=2years and 6 months.​

Mathematics
2 answers:
almond37 [142]3 years ago
7 0
  • Principal=P=2000
  • Rate of interest=12%
  • Time=2years and 6months=2.5years
  • Interest=I

\boxed{\sf I=\dfrac{PRT}{100}}

\\ \sf\longmapsto I=\dfrac{2000(12)(2.5)}{100}

\\ \sf\longmapsto I=\dfrac{24000(2.5)}{100}

\\ \sf\longmapsto I=\dfrac{60000}{100}

\\ \sf\longmapsto I=600

Airida [17]3 years ago
3 0
<h2><u>Given</u></h2>

  • Principal (P) = 2000
  • Rate of interest (R) = 12%
  • Time (T) = 2 years 6 months

<h2><u>To </u><u>Find</u></h2>

  • Simple Interest

<h2><u>Formula</u><u> Using</u></h2>

<u>\large\begin{gathered} {\underline{\boxed{ \rm {\red{S.I \:  =  \:  \frac{P × R × T}{100}  }}}}}\end{gathered}</u>

<h2><u>Basic</u><u> </u><u>Terms</u></h2>

  • <u>Simple Interest -</u> Simple interest is the method of calculating interest charged on the amount invested in a fixed deposit.

  • <u>Principle </u><u>-</u> The principal is the amount due on any debt before interest, or the amount invested before returns.

  • <u>Rate </u><u>-</u> An interest rate is the percentage of principal charged by the lender for the use of its money.

  • <u>Time =</u> Time is duration (in months or years) in Simple Interest.

<h2><u>Solution</u></h2>

As we know that , first we need to convert 2 years 6 months into years.

\sf \ \implies \: 1 \:  \: year \:  =  \: 12 \:  \: months

\sf \implies \: 2 \:  \: years \:   \: and   \: \: 6 \:   \: months \:  =  \: 30 \:  \:months

\sf \implies \: \:\frac{ \cancel{30}  \:  \: ^{2.5  \:  \: years} }{ \cancel{12 \:  }}  \\

\bf{\blue{ Time \:  =  \: 2.5 \:  \: years}}

  • Now , we have to find the Simple interest.

\Large\rm{\orange{ \begin{cases}&#10; \large\begin{gathered} {\underline{\boxed{ \rm {\purple{S.I \:  =  \:  \frac{P × R × T}{100}  }}}}}\end{gathered} \end{cases}}}

<h3><u>Substuting</u><u> the</u><u> values</u><u> </u></h3>

<u>\tt \large \longrightarrow \:  \: S.I \:  =  \:  \frac{2000  \: × \:  12 ×  \: 2.5}{100} \\</u>

<u> </u>

<u>\tt \large \longrightarrow \:  \: S.I \:  = \frac{60000}{100}  \\</u>

<u>\tt \large \longrightarrow \:  \: S.I \:  =  \frac{600 \cancel0 \cancel0}{1 \cancel0 \cancel0}  \\</u>

<u>\tt \large \longrightarrow \:  \: S.I \:  =  \: 600</u>

<u>\large \underbrace{\textrm {{{\color{navy}{Simple Interest \:  =  \: 600}}}}}</u>

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Substituting 25 for t in the expression, we get:

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Thus, after 25 years, there will be 200e^{1.3525}=2003.97=>794 g of the initial sample left in the sample.

794

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We want to find t such that A(t)=200e^{0.0541}

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To Learn More about Isotopes Decay follow link   : brainly.com/question/16355768

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