Answer:
E) we will use t- distribution because is un-known,n<30
the confidence interval is (0.0338,0.0392)
Step-by-step explanation:
<u>Step:-1</u>
Given sample size is n = 23<30 mortgage institutions
The mean interest rate 'x' = 0.0365
The standard deviation 'S' = 0.0046
the degree of freedom = n-1 = 23-1=22
99% of confidence intervals
(from tabulated value).





using calculator

Confidence interval is


the mean value is lies between in this confidence interval
(0.0338,0.0392).
<u>Answer:-</u>
<u>using t- distribution because is unknown,n<30,and the interest rates are not normally distributed.</u>
In both months they had 23,703 and in January they had 13,849
Answer:
(x - y)(j - s).
Step-by-step explanation:
jx + sy - sx - jy
= jx - sx + sy - jy
= x(j - s) - y(j - s)
= (x - y)(j - s).
Step-by-step explanation:
I'm not sure but that's what I'm getting 3k=2 jn simplest form