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Zarrin [17]
1 year ago
15

Wite a differential equation in which y^2= 4(t + 1) is a solution.

Mathematics
1 answer:
Savatey [412]1 year ago
5 0
Answer: dy/dt 2y = 4
Explanation:
The differential equation can be found by taking the derivative of y with respect to t of both sides of this equation.
Derivative of y^2 becomes 2y * dy/dt.
4(t+1) can be distributed to equal 4t + 4.
Derivative of 4t + 4 becomes 4.
Therefore, a possible differential equation is dy/dt * 2y = 4. Can check by separating and integrating.
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Answer:

Part A: The null hypothesis failed to be rejected.

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Step-by-step explanation:

We have an hypothesis test with null and alternative hypothesis H0: p = 0.5 versus Ha: p > 0.5, which has the test statistic z=1.15.

Part A: If the significance level is 0.05, the conclusion depends on the P-value.

If the P-value is below 5%, the null hypothesis is rejected.

The P-value for this right-tailed tes and z=1.15 is:

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This changes the way we calculate the P-value, as we need to compute the two tails.

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