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Stolb23 [73]
2 years ago
14

What is the solution to 3 x 2. 4 greater-than-or-equal-to 3. 0? x greater-than-or-equal-to 0. 2 x greater-than-or-equal-to 0. 6

x greater-than-or-equal-to 1. 8 x greater-than-or-equal-to 2. 5.
Mathematics
1 answer:
IRINA_888 [86]2 years ago
6 0

Answer:

express the following as a fraction and a ratio

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Tammy deposited $520 in the bank account that earns simple interest every year after 5 years she had earned $156 and interest if
aleksley [76]

Answer:

6%.

Step-by-step explanation:

We have been given that Tammy deposited $520 in the bank account that earns simple interest every year after 5 years she had earned $156.

To find the interest rate we will use simple interest formula.

I=P*r*T

I= Interest.

P= Principal amount.

r=Annual interest rate (in decimal form).

T= Time in years.

We have been given that I=156, T=5, P=520

Upon substituting our values in above formula we will get,

156=520*r*5

156=2600r

r=\frac{156}{2600}

r=0.06

Let us multiply 0.06 by 100 to convert annual interest rate in percentage.

0.06*100=6 \text{ percent}

Therefore, the annual interest rate was 6%.

6 0
3 years ago
A train is traveling at a speed of 60 miles per hour. What happens to the number of miles when the number of hours
belka [17]

Answer:

It multiplies

Step-by-step explanation:

if the number of hours changes to example to 2 then you multiply 60 by 2 resulting in 120miles in 2 hours

5 0
3 years ago
Consider the two data sets below:
alina1380 [7]

Answer:

<u><em>Option c) The data sets will have the same values of their interquartile range.</em></u>

<u><em></em></u>

Explanation:

<u>1. The values are in order: </u>they are in increasing oder, from lowest to highest value.

<u>2. Calculate the interquartile range.</u>

<em />

<em>Interquartile range</em>, IQR, is the third quartile, Q3, less the first quartile Q1:

  • IQR = Q3 - Q1

To find the first and the third quartile, first find the median:

<u>Data Set 1</u>: 19, 25, 35, 38, 41, 49, 50, 52, 59

             [19, 25, 35, 38],  41,  [49, 50, 52, 59]

                                         ↑

                                     median = 41

   

<u>Data Set 2</u>: 19, 25, 35, 38, 41, 49, 50, 52, 99

             [19, 25, 35, 38] , 41,  [49, 50, 52, 99]

                                         ↑

                                      median = 41

Now find the median of each subset: the values below the median and the values above the median.

Data set 1: <u>First quartile</u>

                [19, 25, 35, 38],

                            ↑

                           Q1 = [25 + 35] / 2 = 30

                   <u>Third quartile</u>

                   [49, 50, 52, 59]

                                ↑

                                Q3 = [50 + 52] / 2 = 51

                     IQR = Q3 - Q1 = 51 - 30 = 21

Data set 2: <u> First quartile</u>

                   [19, 25, 35, 38]

                               ↑

                               Q1 = [25 + 35] / 2= 30

                  <u>Third quartile</u>

                   [49, 50, 52, 99]

                                ↑

                                Q3 = [52 + 50]/2 = 51

                   IQR = 51 - 30 = 21

Thus, it is shown that the data sets have will have the same values for the interquartile range: IQR = 21. (option c)

This happens because replacing one extreme value (in this case the maximum value) by other extreme value does not affect the median.

<em>An outlier will change the range</em> because the range is the maximum value less the minimum value.

5 0
2 years ago
shanes neighbor pledged 1.25 for every 0.5 miles that shane swims in the charity swim-a-thon.if Shane swims 3 miles,how much mon
Paraphin [41]
3/0.5 = 6
6 x 1.25 = 7.50
4 0
3 years ago
Read 2 more answers
Solve the any quality then identify the graph the solution -3x-3&lt;6
Tanzania [10]

Answer:

Step-by-step explanation:

-3X-3<6

-3X<9

X>-3    (NOTICE THE SIGN CHANGE BECAUSE WE DIVIDED BY A NEGATIVE NUMBER)

(-3,00) INTERVAL NOTATION

7 0
3 years ago
Read 2 more answers
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