I don't know but I think it is B) The slope is negative, and a linear model is a good fit for the data.
Answer : 96
x – y = 16
--------> equation 1

x is the higher grade and y is the lower grade
We solve the first equation for y
x - y = 16
-y = 16 -x ( divide each term by -1)
y = -16 + x
Now substitute y in second equation



Take common denominator to combine fractions


Add 8 on both sides

Multiply both sides by 
x = 96
We know x is the higher grade
96 is the higher grade of Jose’s two tests.
Answer:
0
Step-by-step explanation:
−2−(−4)−2
=2−2
=0
V = lwh
2x³ + 17x² + 46x + 40 = l(x + 4)(x + 2)
2x³ + 12x² + 16x + 5x² + 30x + 40 = l(x + 4)(x + 2)
2x(x²) + 2x(6x) + 2x(8) + 5(x²) + 5(6x) + 5(8) = l(x + 4)(x + 2)
2x(x² + 6x + 8) + 5(x² + 6x + 8) = l(x + 4)(x + 2)
(2x + 5)(x² + 6x + 8) = l(x + 2)(x + 4)
(2x + 5)(x² + 2x + 4x + 8) = l(x + 4)(x + 2)
(2x + 5)(x(x) + x(2) + 4(x) + 4(2)) = l(x + 4)(x + 2)
(2x + 5)(x(x + 2) + 4(x + 2)) = l(x + 4)(x + 2)
(2x + 5)(x + 4)(x + 2) = l(x + 4)(x + 2)
(x + 4)(x + 2) (x + 4)(x + 2)
2x + 5 = l
Answer:
x = 34
Step-by-step explanation:
ΔABD and ΔBCD are both isosceles triangles
In ΔABD
AB =AD, hence ∠ABD = ∠ADB ( base angles are equal )
∠ABD =
=
= 68°
∠DBC = 180° - 68° = 112° ( straight angle )
∠BCD = x =
=
= 34