Given:
Total amount of Mingfa and her sister = $130
If Mingfa amount increased by $10, then the new amount is equal to three times of as much money as her sister.
To find:
How much money does Mingfa actually have?
Solution:
Let, Mingfa have $x and her sister has $y initially. Then,
...(i)
If Mingfa amount increased by $10, then the new amount is equal to three times of as much money as her sister.
...(ii)
Substitute the value of x from (ii) in (i).
Divide both sides by 4.
Putting
in (i), we get



Therefore, Mingfa have $95.
Answer:
![\displaystyle [-2, 7]](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5B-2%2C%207%5D)
Step-by-step explanation:
You want to eradicate one pair of variables so they are set to zero. It does not matter which pair is selected:

{½[4x + 2y = 6]
{−2x + 2y = 18
>> 
Plug this back into the system to get the x-value of 
I am joyous to assist you at any time.
Answer:
D. Subtract 9y from both sides of the equation.
Step-by-step explanation:
A. Divide both sides of the equation by 36.
B. Multiply both sides of the equation by 6.
C. Add 9y to both sides of the equation.
D. Subtract 9y from both sides of the equation.
Given:
9y - 6x = 36
To solve for x
Step 1: subtract 9y from both sides
9y - 6x - 9y = 36 - 9y
- 6x = 36 - 9y
Step 2: Divide both sides by -6
- 6x / -6 = (36 - 9y) / - 6
x = (36 - 9y) / - 6
The answer is
x = (36 - 9y) / - 6