This is a problem in "binomial probability." Either the archer hits his target or he does not. This experiment is performed 5 times (so that n=5), and the probability that the archer will hit the target is 0.7 (so that p=0.7).
We need to find the binomial probability that x=3 when the possible outcomes are {0, 1, 2, 3, 4, 5}.
You could use a table of binomial probabilities to evaluate the following:
P(5, 0.7, 3).
Alternatively, you could use a TI-83 or TI-84 calculator and its built-in "binompdf( " function.
I evaluated binompdf(5,0.7,3) and obtained the result 0.309.
You'll have to multiply 0.7 by 120.
120*0.7 = n
n is the number that is 70% of 120
120 * 0.7 = 84
Hope this helps :)
We can use pythagorean theorem:
a^2 + b^2 = c^2
4 + 9 = c^2
13 = c^2
sqrt of 13 = c
Hope this helps!
Answer:
97.75
Step-by-step explanation:
15% of 85 is 12.75
12.75 + 85 = 97.75
Hope this helps have a nice day
