Answer:
A or (2x+1)/(x-1)
Step-by-step explanation:
Let's simplify the top of the fraction first.
1. Simplify the numerator.
2x^2 -7x-4=(2x+1)(x-4)
2. Simplify the denominator.
x^2-5x+4=(x-4)(x-1)
Now we have:
((2x+1)(x-4))/((x-4)(x-1))
We see that there is an (x-4) both on the numerator and denominator.
We can remove (x-4) by division.
Doing that, we have:
(2x+1)/(x-1) or A
Answer:
False because on the left side of the equation you are adding 18 and 35 first and on the right you are multiplying 35 and 4 first. This will give you an unequal equation when solved.
Let's solve each side
(18+35)*4=212
but 18+(35*4)=158
6x+3>3x+30
The thing about solving inequalities, you just need to treat the symbol, which is the less than symbol in this case, as an equal sign.
So our problem becomes: 6x+3=3x+30
Now we solve this like a normal algebra problem.
First, get all the variables on one side. Since 3x is smaller than 6x, we'll get rid of that by subtracting it from each side.
3x+3=30 is what we end up with.
Now to get the variable alone and get rid of that constant. To do that, we are going to subtract 3 from each side.
We end up with 3x=27
Now, to get the 'x' alone, we need to divide each side by 3.
x=9 is what we end up.
BUT WE FORGOT TO DO SOMETHING
We started this as an inequality problem, so we need to end it as an inequality solution.
Since there wasn't any negatives we need to worry about (Which is something else entirely) we just need to transfer the symbol we started with down.
x>9
Any Questions?
The Answer to your Question is V=a3
