Help me with this algebra equation

The percent frequency distributions of job satisfaction scores for a sample of information systems (IS) senior executives and mi

tiny-mole [99]

Corrected Question

a. Develop a probability distribution for the job satisfaction score of a senior executive.

b. Develop a probability distribution for the job satisfaction score of a middle manager.

c. What is the probability a senior executive will report a job satisfaction score of 4 or 5?

d. What is the probability a middle manager is very satisfied?

Answer:

(c)0.83

(d)0.28

Step-by-step explanation:

The percent frequency distributions of job satisfaction scores os give below:

$\left|\begin{array}{c|c|c}$Job Satisfaction Score&$IS Senior Executives(\%)&$IS Middle Managers(\%)\\1&5&4\\2&9&10\\3&3&12\\4&42&46\\5&41&28\end{array}\right|$

(a)Probability distribution for the job satisfaction score of a senior executive.

$\left|\begin{array}{c|c}$Job Satisfaction Score&$Relative Frequency (f_1(x))\\------&------\\1&0.05\\2&0.09\\3&0.03\\4&0.42\\5&0.41\end{array}\right|$

(b)Probability distribution for the job satisfaction score of a middle manager.

$\left|\begin{array}{c|c}$Job Satisfaction Score&$Relative Frequency (f_2(x))\\1&0.04\\2&0.10\\3&0.12\\4&0.46\\5&0.28\end{array}\right|$

(c)Probability a senior executive will report a job satisfaction score of 4 or 5

P(a senior executive will report a job satisfaction score of 4 or 5)

$=f_1(4)+f_1(5)\\=0.42+0.41\\=0.83$

(d)Probability a middle manager is very satisfied

The probability a middle manager is very satisfied

$=f_2(5)\\=0.28$

7 0

3 years ago

Newborn males have weights with a mean of 3272.8 g and a standard deviation of 660.2 g. Newborn females have weights with a mean

Maksim231197 [3]

The correct option is: a female who weighs 1500 g

Explanation

Formula for finding the z-score is: $z= \frac{X-\mu}{\sigma}$

Newborn males have weights with a mean $(\mu)$ of 3272.8 g and a standard deviation $(\sigma)$ of 660.2 g.

So, the z-score for the newborn male who weighs 1500 g will be.......

$z(X=1500)=\frac{1500-3272.8}{660.2}=-2.685... \approx -2.69$

According to the normal distribution table, $P(z=-2.69)=0.0036 = 0.36\%$

Now, newborn females have weights with a mean $(\mu)$ of 3037.1 g and a standard deviation $(\sigma)$ of 706.3 g.

So, the z-score for the newborn female who weighs 1500 g will be.......

$z(X=1500)=\frac{1500-3037.1}{706.3}=-2.176... \approx -2.18$

According to the normal distribution table, $P(z=-2.18)=0.0146 = 1.46\%$

As we can see that the probability that a newborn female has weight of 1500 g is greater than newborn male, so a newborn female has the weight of 1500 g that is more extreme relative to the group from which he came.

5 0

3 years ago

How many square inches are in 60 square feet

Dahasolnce [82]

Answer:8640

Step-by-step explanation: 60 square feet would be 8640.

3 0

3 years ago

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Need help to write equations for 5, 6 & 7

Nutka1998 [239]

5)
The x-values go up by 1: -2, -1, 0, 1, 2
The y values are always 3 times the previous value.
This is an exponential function.

$y = a(b)^x$

We need to find a and b.
Look at x = 0.
For x = 0, y = 4.

$y = a(b)^x$

$4 = a(b)^0$

Since b^0 = 1, this simplifies to

$4 = a$

Now we know a = 4. We have

$y = 4(b)^x$

Look at x = 1. For x = 1, y = 12.

$12 = 4(b)^1$

$12 = 4b$

$b = 3$

Now that we know a and b, we can write the function.

$y = 4(3)^x$

Now that you have the function written out, notice the following.
In the exponential equation we found, the number raised to x
is the number you multiply each y value to get the next y value.
In this case, each y value is 3 times the previous one, so you have 3^x.
The way you find "a" in the exponential equation is to look at the y-coordinate
when x = 0. When x = 0, b^x is 1, so b^x drops out, and you get "a" equal to
the y-value. In this case, when x = 0, y = 4, so "a" is 4.
With b = 3, and a = 4, you can quickly write:
y = 4(3)^x.

7 0

4 years ago

The function y= 19,800/x is a rational function. Use this function to answer each question. What are the asymptotes of the funct

Ilya [14]

Answer:

Step-by-step explanation:

Given the function y = 19800/x

Vertical asymptote occurs at when f(x) = 0 where;

f(x) is the denominator of the given function.

From the expression given: f(x) = x

Since f(x) => 0, hence x = 0

To get the horizontal asymptote, we will look at the degree of the numerator and denominator. If the degree of numerator is less than the denominator, the horizontal asymptote will be zero. From the function, we can see that the degree of the numerator is zero (being a constant) and that of the denominator is 1.

Since 0<1, hence the horizontal asymptote is 0

x = 0, y = 0

5 0

3 years ago

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