All categories

2 years ago

In tintern abbey who accompanies the speaker in the poem

SAT

1 answer:

Delicious77 [7]2 years ago

7 0

The person who accompanies the speaker in the poem titled Tintern Abbey is found to be; His Sister

<h3>Who is the companion of the speaker in the poem?</h3>

The full title of the poem was "Lines Composed a Few Miles Above Tintern Abbey," written by In William Wordsworth's .

In the poem, we see that the speaker is visiting a place he has seen once before. However, this time, he sees it in a different way and as such the speaker is now able to stop and appreciate the natural beauty right before his eyes.

Finally wee see that his companion is his sister because he said the following;

"For thou art with me here upon the banks

.......May I behold in thee what I was once,

My dear, dear Sister!"

Read more about poem speaker at; brainly.com/question/2506522

You might be interested in

Select the correct statement(s) regarding Passive Optical Networks (PONs).

natta225 [31]

All the given statement(s) regarding Passive Optical Networks (PONs) are correct.

<h3>What is Passive Optical Networks?</h3>

A passive optical network (PON) is defined as a system commonly used by telecommunications network providers that brings fiber optic cabling and signals all or most of the way to the end user. Depending on where the PON terminates, the system can be described as fiber to the curb, fiber to the building or fiber to the home.

Now, there are different types of passive optical network's (PON's) such as;

APON which is ATM Passive Optical Networks.

BPON which is Broadband PON.

EPON which is Ethernet PON.

GE-PON which means Gigabit Ethernet PON.

GPON which means Gigabit Ethernet PON.

Looking at the options and comparing with the definition of passive optical network's (PON's), we can say that all the statements are correct.

The missing options are;

a. PONS does not require the use of active amplification between the CO to the subscriber

b. PONS operates over SMF optical cables

c. PONS uses passive splitters to distribute signals to subscribers

d. the PONS ONT located at the subscribers location is owned and operated by the service provider

e. all statements are correct

Read more about Networks at; brainly.com/question/8118353

#SPJ1

3 0

2 years ago

You are picking an order and come across a box of perfume

densk [106]

Free pts?? Is there a question??

7 0

3 years ago

What is the range of the data in this stem-and-leaf plot? 2 14 19 32. 5.

vovangra [49]

Answer:

We'll be using the 5 numbers in your question.

In order to solve this problem, we need to know what range is.

The range is the spread of your data from the <u>lowest</u> to the <u>highest</u> value.

In order to find the range, we need to order the values from least to greatest.

Note: No picture of the stem-and-leaf plot is given in the question.

From least to greatest:

2, 5, 14, 19, 32.

Next, find the maximum and the minimum values.

Minimum: 2

Maximum: 32

Lastly, subtract the maximum and the minimum:

32-2=30.

Your range is 30.

6 0

2 years ago

A good rule of thumb is to design the horizontal stabilizer so that its area is about 1/6 to 1/8 of the area of the wing. If the

mars1129 [50]

Answer:

Answer:

Stabilizer with area = 14 cm².

Step-by-step explanation:

Area of the wing = 101.25 cm²

Rule of the thumb is that area of stabilizer must be about 1/6 to 1/8 of the area of wing. So, first we calculate 1/6 of the area of the wing and 1/8 of the area of the wing. Area of stabilizer must be in between these two numbers.

1/6 of the area of wing = \frac{1}{6} \times 101.25 = 16.87561×101.25=16.875

1/8 of the area of wing = \frac{1}{8} \times 101.25 = 12.65681×101.25=12.656

This means, the area of horizontal stabilizer must be in between 12.656 cm² and 16.875 cm². From the given options only one option lies in between these two numbers and that is 14 cm²

Therefore, area of a good stabilizer design from the given options would be 14 cm²

7 0

2 years ago

Read 2 more answers

In a recent year, about 22% of Americans 18 years and older are single. What is the probability that in a random sample of 200 A

Pie

Using the normal approximation to the binomial, it is found that there is a 0.0107 = 1.07% probability that more than 30 are single.

<h3>Normal Probability Distribution</h3>

The z-score of a measure X of a normally distributed variable with mean $\mu$ and standard deviation $\sigma$ is given by:

$Z = \frac{X - \mu}{\sigma}$

The z-score measures how many standard deviations the measure is above or below the mean.

Looking at the z-score table, the p-value associated with this z-score is found, which is the percentile of X.

The binomial distribution is the probability of x successes on n trials, with p probability of a success on each trial. It can be approximated to the normal distribution with $\mu = np, \sigma = \sqrt{np(1-p)}$ .

In this problem, the proportion and the sample size are, respectively, p = 0.22 and n = 200, hence:

$\mu = np = 200(0.22) = 44$

$\sigma = \sqrt{np(1 - p)} = \sqrt{200(0.22)(0.78)} = 5.8583$

The probability that more than 30 are single, using continuity correction, is P(X > 30.5), which is <u>1 subtracted by the p-value of Z when X = 30.5</u>, hence:

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{30.5 - 44}{5.8583}$

Z = -2.3

Z = -2.3 has a p-value of 0.0107.

0.0107 = 1.07% probability that more than 30 are single.

More can be learned about the normal distribution at brainly.com/question/24663213

6 0

1 year ago