Step-by-step explanation:
Since X is given to you (in this case, it’s 7), all you have to do is plug it into the equation.
1. -2(7) + 10
When a variable or a number is directly outside a number, it means you should multiply the two numbers, no matter what.
Now that we know this: -2 * 7 = (-14) When a negative is multiplied by a positive, it turns out negative.
2. (-14) + 10: Let’s say (for instance), that I owe 14 dollars to a friend. If I pay 10 of it, how much do I owe my friend? It would be -4 because you’re still in debt, and haven’t payed your friend all of her 14 dollars back.
3. You should come up with an answer of (-4) because of all of the steps given.
If something doesn’t make sense, please make a note of it and tell me. Otherwise, have a splendid day.
Answer:
Graphs behave differently at various x-inter cepts. Sometimes the graph will cross over the x-axis at an intercept. Other times the graph will touch the x-axis and bounce off.
Suppose, for example, we graph the function. f(x) = (x+3)(x - 2)²(x+1)³.
Notice in the figure below that the behavior of the function at each of the x-intercepts is different.
Ur gonna have to pick an equation and solve for a variable.
2x - 2y = 6
2x = 2y + 6 ...divide everything by 2 because u want x by itself
x = y + 3
now we sub y + 3 in for x in the other equation
14x - 2y = 78
14(y + 3) - 2y = 78...distribute thru the parenthesis
14y + 42 - 2y = 78...subtract 42 from both sides, cancelling the 42 on the left
-42 -42
-----------------------
14y - 2y = 36 ...simplify
12y = 36...divide by 12 on both sides, cancelling out the 12 on the left
y = 36/12
y = 3
now , we already know that x = y + 3...and we know y = 3...so sub in 3 for y and solve for x
x = y + 3
x = 3 + 3
x = 6
solution is (6,3)
it is always a good idea to check ur answer by subbing it into one or both of the equations to see if it is correct
2x - 2y = 6......(6,3)...x = 6 and y = 3
2(6) - 2(3) = 6
12 - 6 = 6
6 = 6 (correct)
so yes, ur solution is (6,3)
Answer:
2
Step-by-step explanation:


<em>good luck, i hope this helps :)</em>