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LenKa [72]
1 year ago
15

The perimeter of a square is 24 feet. What is the area in square feet

Mathematics
2 answers:
julsineya [31]1 year ago
8 0
<h3>Question -:</h3>

The perimeter of a square is 24 feet. What is the area in square feet.

<h3>Explanation -:</h3>

In this question we are provided with the perimeter of the square and we are asked to calculate the area of the square. First we will calculate the side of the square and then we will calculate the area.

\small{ \underline{ \underline{ \red{\rm{ Calculating  \: the \:  side \: of \: the \: square}}}}}

We know,

\star \:  \small\boxed{ \rm{ Perimeter_{(square)} = 4 × side}}

Substituting the values we get

\small\bf 24 = 4 × s

\small\sf{ → \dfrac{24}{4} = s}

\small\sf{ → s = 6  \: feet}

\small{ \underline{ \underline{\rm \red{ Now, we \:  will  \: calculate \:  the \:  area }}}}

We know,

\star \: \small \boxed{{\rm Area_{(square)} = side × side}}

Substituting the values we get

\small\rm {Area_{(square)} = (6 × 6) feet² = 36 \:  feet²}

Hence, the area of the square is 36 feet².

elixir [45]1 year ago
5 0

Answer:

Step-by-step explanation:

Remark

You need 2 formulas to solve this. Use perimeter first and then area.

Formulas

P = 4s

Area = s^2

Givens

Perimeter = 24 feet

Solution

<em>P = 4*s  </em>                 Substitute the value for P

24 feet = 4s           Divide both sides by 4

24/4 = 4s/4

6 = s

<em>Now use the area formula</em>

Area = s^2             Substitute 6 for s

Area = 6^2

Area = 36 feet^2

Answer

Area = 36 ft^2

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boyakko [2]

Answer: a²+b² = -99/2

Step-by-step explanation:

Since we are given two equations, this equations will be solved simultaneously to get a² and b²

a³ - 3ab² = 47 ... 1

b³ - 3a² b = 52... 2

From 1, a(a² - 3b²) = 47...3

From 2, b(b² - 3a²) = 52... 4

Adding 3 and 4, we have;

a²+b²-3b²-3a² = 99 (note that a and b will no longer be part of the equations as they have been factored out)

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3 years ago
if you roll a fair 6-sided die 9 times, what is the probability that at least 2 of the rolls come up as a 3 or a 4?
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Using the binomial distribution, it is found that there is a 0.857 = 85.7% probability that at least 2 of the rolls come up as a 3 or a 4.

For each die, there are only two possible outcomes, either a 3 or a 4 is rolled, or it is not. The result of a roll is independent of any other roll, hence, the <em>binomial distribution</em> is used to solve this question.

Binomial probability distribution

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

C_{n,x} = \frac{n!}{x!(n-x)!}

The parameters are:

  • x is the number of successes.
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  • p is the probability of a success on a single trial.

In this problem:

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  • Of the six sides, 2 are 3 or 4, hence p = \frac{2}{6} = 0.3333

The desired probability is:

P(X \geq 2) = 1 - P(X < 2)

In which:

P(X < 2) = P(X = 0) + P(X = 1)

Then

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{9,0}.(0.3333)^{0}.(0.6667)^{9} = 0.026

P(X = 1) = C_{9,1}.(0.3333)^{1}.(0.6667)^{8} = 0.117

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P(X < 2) = P(X = 0) + P(X = 1) = 0.026 + 0.117 = 0.143

P(X \geq 2) = 1 - P(X < 2) = 1 - 0.143 = 0.857

0.857 = 85.7% probability that at least 2 of the rolls come up as a 3 or a 4.

For more on the binomial distribution, you can check brainly.com/question/24863377

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