Given equations : Equation A: 4y -3x =16 and
Equation B: -x-8y =3.
We are given a<em> point (-5,0.25) plugging it in first equation</em>
4(0.25) -3(-5) =16
1+15 =16.
16 =16 <em>: Satisfies first equation.</em>
Plugging (-5,0.25) it in second equation.
-(-5)-8(0.25) =3.
5 - 2 = 3.
3=3 <em>: Satisfies first equation.</em>
<h3>Therefore, they are the only values that make both equations true.</h3>
Answer: The first interval:0 ≤ x ≤ 20
Procedure
You have to solve this inequality
-2x^2 +40x +600 ≥ 600
-2x^2 +40x ≥ 0
-x^2+20x ≥ 0
x^2 - 20 x ≤ 0
x(x-20) ≤ 0
That is only possible if the two factors have different signs.
Let's examine the possibilities
x ≥ 0 and x -20 ≤ 0⇔x≤20, that is 0≤x≤20
The other possibility is
x ≤ 0 and x - 20 ≥ 0 ⇔x≥20. This conditions is not possible.
So the solution is 0≤x≤20
Answer:
2ft
Step-by-step explanation:
If you have a 3x3 you have a 9ft Sq paper. To have five feet left the removed square must be 4 square feet. 2x2 = 4 therefore 2ft per side
Blue=4
red=8
white=4
I hope you are able to solve the question on your one shortly!
Answer:
7/10
Step-by-step explanation:
the '7' in 0.7 is in the tenths place of the decimal. So put 7 over 10 to create the fraction 7/10.