It would be c because 1 cm. is equal to 10 mm
Answer:
Ok, as i understand it:
for a point P = (x, y)
The values of x and y can be randomly chosen from the set {1, 2, ..., 10}
We want to find the probability that the point P lies on the second quadrant:
First, what type of points are located in the second quadrant?
We should have a value negative for x, and positive for y.
But in our set; {1, 2, ..., 10}, we have only positive values.
So x can not be negative, this means that the point can never be on the second quadrant.
So the probability is 0.
Answer:
The correct option is;
The graph is a line that rises steeply from left to right and passes through the origin
Step-by-step explanation:
The given equation is y = 110·x
Comparing the given equation to the general equation of a straight line, y = m·x + c
Where;
m = The slope of the straight line graph
c = The y-intercept
We have;
The slope of the given equation, y = 110·x = 110
The y-intercept, which is given by the constant c in the given equation = (0, 0)
Therefore, by the slope of the equation, for each unit increase in x, y increases by 110, therefore, the graph is a straight line that rises steeply and passes through the origin
Let H = Henry
Let R = Roger
Let S = Sandy
H = 3R -> H = 3y
S = 9 + H -> S = 9 + 3y
R = y
Sandy has 3y + 9 CDs more than Roger.
Answer:
d
Step-by-step explanation:
cannot be a or c cause it has a negative sign in front of it causing it to reflect over y axis. Cannot be B cause it doesn't have two coefficients with X. I also graphed it.
