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2 years ago

George is going shopping for a new car to replace his old one. Which of these costs would be

Business

1 answer:

uranmaximum [27]2 years ago

4 0

The cost that would relevant in the choice of a new car is the the cost to operate the new vehicles.

<h3>What cost would be relevant?</h3>

The cost that would be relevant in the choice of a new car is the cost that is dependent on the type of car chosen. The cost to operate the new car would depend on the type of car chosen. If George buys a more fuel efficient car, the cost of running the car would be cheaper.

To learn more about cost, please check: brainly.com/question/27127934

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According to the "adapting to change" box, which professional is best able to detect the financial irregularities that often acc

lutik1710 [3]

According to the "adapting to change" box, the professional that is best able to detect the financial irregularities that often accompany fraud in an organization is Control process.

<h3>What is control process?</h3>

Controlling involves assessing the performance of a company and modifying the financial performance.

This is done for credibility and to meet the company's objectives, goals and plans.

Control process serves as yardstick to which the goal of business or company is achieved. Managers of company engage in control process.

Therefore, According to the "adapting to change" box, The professional that is best able to detect the financial irregularities that often accompany fraud in an organization is Control process.

Learn more on control process below

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7 0

1 year ago

A company incurs advertising costs of $10,000. The company's three selling departments have the following sales: Department 1—$1

erik [133]

Answer:

The amount of advertising allocated to:

Department 1: $1,250

Department 2: $3,750

Department 3: $5,000

Explanation:

Total sales of the company = Sales of Department 1 + Sales of Department 2 + Sales of Department 3 = $10,000 + $30,000 + $40,000 = $80,000

Percent of sales of three selling departments:

Department 1 = ($10,000/$80,000)x100% = 12.5%

Department 2 = ($30,000/$80,000)x100% = 37.5%

Department 3 = ($40,000/$80,000)x100% = 50%

Advertising is allocated based on percent of sales. The amount of advertising allocated to:

Department 1 = 12.5% x $10,000 = $1,250

Department 2 = 37.5% x $10,000 = $3,750

Department 3 = 50% x $10,000 = $5,000

5 0

3 years ago

Find the expected return for Jackson Corporation. Round to the nearset hundredth percent. Answer in the percent format. Do not i

Maksim231197 [3]

Question:

Jackson Corporation has expected return of 12% during recession, 20% during normal, and 40% during boom state of economy. Probability of recession, normal and boom states of economy is 0.25, 0.50, and 0.25 respectively. Find the expected return for Jackson Corporation. Round to the nearset hundredth percent. Answer in the percent format. Do not include % sign in your answer (i.e. If your answer is 4.33%, type 4.33 without a % sign at the end.)

Answer:

23.00

Explanation:

Given:

For Jackson Corporation:

Expected return during recession = 12%

Expected return during normal = 20%

Expected return during boom = 40%

For Economy:

Probability of recession = 0.25

Probability of normal = 0.50

Probability of boom = 0.25

Required:

Find the expected return for Jackson Corporation.

To find expected return, use the expression below:

Expected return = (Probability of Recession * Returns at Recession) + (Probability of Normal * Returns at Normal) + (Probability of Boom * Returns at Boom)

Using the expression above, expected return for Jackson corporation will be calculated as:

Expected return = (25×12%)+(0.50×20%)+(0.25×40%)

= 3 + 10 + 10

= 23%

Expected return for Jackson corporation is 23.00

5 0

3 years ago

Pressure with Two Liquids, Hg and Water. An open test tube at 293 K is filled at the bottom with 12.1 cm of Hg, and 5.6 cm of wa

Radda [10]

Answer:

$1170839.28 dyn/cm^2$

16.9816 psia

$117.083928 kN/m^2$

Explanation:

To calculate the absolute pressure in the bottom of tube we need to sum the atmosferic and gauge pressure.

$P_{abs}=P_{atm}+P_G$

And the gauge pressure is given by the contributions of columns of water ( $P_{w}$ ) and mercury( $P_{Hg}$ ), we can calculate the contribution of each column as:

$P= \rho g h$ (*)

where $\rho$ is the respective density, g gravity and h is height.

So we have all the data required to use the above equations ( $P_{atm}$ , height and density of each column) we only need to be carefully with the units.

For simplicity we can to express all pressure contributions in mmHg ( $P_{atm}$ , $P_{w}$ and $P_{Hg}$ ). Note that the units "x" mmHg means the pressure at the bottom of a column of mercury of "x" mm high. For example, in this case we have a column 12.1 cm of Hg, that is a column of 121 mmHg (passing from cm to mm only requires multiply by 10) pressure exerted by that column is 121 mmHg.

Now pressure of 5.6 cm (56 mm) of water would be 56 mm of water, but it is not the same that mmHg, since the density of water is lower, the pressure exerted by 1 mm of water is lower than the exerted by 1 mm of Hg. The conversion between mmHg and mm of water is given by the relation between the densities.

$mmHg=\frac{\rho_w*mmH_2O}{\rho_{Hg}}$

$mmHg=\frac{0.998*mmH_2O}{13.55}=0.0737 mmH_2O$

And pressure of water in mmHg is

$0.0737*56=4.1246 mmHg$

The absolute pressure is:

$P_{abs}=P_{atm}+P_G= 756 + 121 + 4.1246 = 881.1246 mmHg = 88.11246cmHg$

To pass to dyn/cm^2 units we need to use the equation (*)

$P= \rho g h = 13.55 \frac{g}{cm^3} * 980.665 \frac{cm}{s^2} * 88.11246 cmHg = 1170839.28 \frac{g}{cm s^2} = 1170839.28 \frac{dyn}{cm^2}$

Note: We need to use cm Hg for units coherence

Now passing from dyn/ $cm^2$ to kN/ $m^2$ (or kPa) we need to consider that 1 dyn is $10^{-8}$ kN and 1 $cm^2$ is $10^{-4} m^2$ .

$1170839.28 \frac{dyn}{cm^2} * \frac{10^{-8}kN}{1 dyn}*\frac{cm^2}{10^{-4}m^2}=117.083928kN/m^2$

Now passing kN/ $m^2$ to psia. We need to consider that 1 psia is 6.89476.

$117.083928kN/m^2*\frac{1psia}{6.89476kN/m^2}=16.9816 psia$

8 0

3 years ago

For an analysis of the salaries of your company, you plot the salaries of all employees against the number of years they have w

Arisa [49]

Answer:

1. That values that you must plot are:

(1, 4.08))

(20, 5.08)

(40, 6.18)

2. Yes, the plot of those three points is straight enough.

Explanation:

<em><u>A. What are the values you will plot? </u></em>

The x-ccordinate of your plot is still the number of years the exmployees have worked for the company.

The y-coordinate of your plot is the the base-10 logarithm of the salary.

Therefore:

<u>1) A part-time shipping clerk</u>: 1 year, $12,000

⇒ $(1,log_{10}12,000)=(1,4.08)$

<u>2) A manager</u>: 20 years, $120,000

⇒ $(20,log_{10}120,000)=(20,5.08)$

<u>3) The CEO</u>: 40 years ago, $1,500,000

⇒ $(40,log_{10}1,500,000)=(40,6.18)$

Summarizing, the points to plot are:

(1, 4.08)

(20, 5.08)

(40, 6.18)

<u><em>B. Will the plot of these three points be straight enough?</em></u>

To find whether the plot is straight enoguh, you may either plot them, make a regression, or, since they are only three points, you can whether the change of rate of the points is constant.

<u>Change of rate of the first two points, r</u>:

r = rise/run = Δy / Δx = (5.08 - 4.08) / (20 - 1) =1.00/19 ≈ 0.05

<u>Change of rate of the second and the third points, r</u>:

r = rise/run = Δy / Δx = (6.18 - 5.08) / (20 - 1) = 0.05

Since both rate of changes are equal (or reasonably equal) the plot is straight enough.

4 0

3 years ago