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SIZIF [17.4K]
3 years ago
9

School A has 480 students and 16 classrooms. School B has 192 students and 12 classrooms.

Mathematics
1 answer:
boyakko [2]3 years ago
3 0

Answer:96

Step-by-step explanation:

A; 480/16 = 30 students per classroom

B: 192/12 =16 students per classroom

we need x such that \frac{480-x}{16} = \frac{192+x}{12}

which means

(480-x )* 12 should be equal to (192+x) * 16

5,760 - 12x = 3,072+16x

5,760 - 3,072 = 12x + 16x

2,688 = 28x

x = 96

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***PLEASE HELP I'M TIMED***
Natalija [7]

Answer:

Domain and Range of g(f(x)) are 'All real numbers' and {y | y>6 } respectively

Step-by-step explanation:

We have the functions, f(x) = eˣ and g(x) = x+6

So, their composition will be g(f(x)).

Then, g(f(x)) = g(eˣ) = eˣ+6

Thus, g(f(x)) = eˣ+6.

Since the domain and range of f(x) = eˣ are all real numbers and positive real numbers respectively.

Moreover, the function g(f(x)) = eˣ+6 is the function f(x) translated up by 6 units.

Hence, the domain and range of g(f(x)) are 'All real numbers' and {y | y>6 } respectively.

6 0
3 years ago
Read 2 more answers
I need help please i​
balandron [24]

Answer:

<em>2 7/24</em>

Step-by-step explanation:

<em>First we have to add the gallons of two cow of each owner:</em>

<em>Hank's cows: </em><em>4 3/4 + 4 1/8</em>

<em>Add the whole numbers:</em>

<em>4 + 4 = 8</em>

<em>Now for 3/4 and 1/8 </em>

<em>Find common</em>

<em>6/8 + 1/8</em>

<em>= 7/8</em>

<em>Put together :</em>

<em>8 7/8</em>

<em>Debra's cows: </em><em>5 1/2 + 5 2/3</em>

<em>Add the whole number</em>

<em>5 + 5 = 10</em>

<em>Now for 1/2 and 2/3</em>

<em>3/6 + 4/6</em>

<em>1 1/6</em>

<em>10 + 1 1/6 </em>

<em>= 11 1/6</em>

<u><em>Since now we know that:</em></u>

<u><em>Hank - </em></u><em>8 7/8</em>

<u><em>Debra - </em></u><em>11 1/6</em>

<em>we can solve the question:</em>

<em>How many more gallons of milk did Debra's two cows produce on that compared to Hank's two cows?</em>

<em>Solution:</em>

<em>11 1/6 - 8 7/8</em>

<em>Subtract whole number</em>

<em>11 - 8 = 3</em>

<em>Now for 1/6 and 7/8</em>

<em>4/24 - 21/24</em>

<em>4-21/24</em>

<em>-17/24</em>

<em>2 7/24</em>

<em />

<u>~lenvy~</u>

7 0
3 years ago
Read 2 more answers
Find the area of the largest rectangle (with sides parallel to the coordinate axes) that can be inscribed in the region enclosed
garik1379 [7]
F(x) = 18-x^2 is a parabola having vertex at (0, 18) and opening downwards. 
g(x) = 2x^2-9 is a parabola having vertex at (0, -9) and opening upwards. 
By symmetry, let the x-coordinates of the vertices of rectangle be x and -x => its width is 2x. 
Height of the rectangle is y1 + y2, where y1 is the y-coordinate of the vertex on the parabola f and y2 is that of g.
 => Area, A 
= 2x (y1 - y2) 
= 2x (18 - x^2 - 2x^2 + 9) 
= 2x (27 - 3x^2) 
= 54x - 6x^3 
For area to be maximum, dA/dx = 0 and d²A/dx² < 0 
=> 54 - 18x^2 = 0 
=> x = √3 (note: x = - √3 gives the x-coordinate of vertex in second and third quadrants) 

d²A/dx² = - 36x < 0 for x = √3 
=> maximum area 
= 54(√3) - 6(√3)^3 
= 54√3 - 18√3 
= 36√3. 
4 0
3 years ago
How much material is used
Neko [114]
This question is essentially asking you to find the surface area of the box.
The formula for SA on a rectangular prism is: 2(L*W+L*H+W*H)
L=Length W=Width H=Height

Lets input the information we know:
2(20*8+20*30+8*30)
Follow BEDMAS
2(160+600+240)
2(760+240)
2(1000)
2*1000
=2000

The box will need 2000 centimeters squared of material.

Hope this helps!
-Benjamin
5 0
4 years ago
What is the distance between (10, 6) and (-2, -3)
Helga [31]

Answer:

15 units.

Step-by-step explanation:

The distance between the points (x1, y1) and (x2, y2) is

√(x1-y1)^2 + (y1-y2)^2))

So here it is:

√(10- -2)^2 + (6- -3)^2)

= √(144+81)

=  √225

= 15.

4 0
4 years ago
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