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3 years ago

Which of the following notations correctly describe the end behavior of the polynomial graphed below?

Mathematics

1 answer:

algol133 years ago

4 0

The right answer is C

Let me to explain. From the graph we know that the vertex of this parabola is $V(0,8)$ . This is a maximum y-value. We also know that the parabola opens downward, so the leading coefficient is negative. Given that the function is even and the leading coefficient is negative, it follows that the graph falls to the left and right. In a mathematical language this is:

$x \rightarrow -\infty, f(x) \rightarrow -\infty \\ \\ x \rightarrow \infty, f(x) \rightarrow -\infty$

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Probability and statistics

PtichkaEL [24]

Answer:

Step-by-step explanation

it is a random variable but is continuos as it doesn't change.

8 0

3 years ago

Factorise fully the following: a) x² + 2x b) 2x² - 6x c) 15x - 10x³ d) 9x² + 3x³

Lostsunrise [7]

Answer:

a) $x(x+2)$

b) $2x(x-3)$

c) $5x(3-2x^2)$

d) $3x^2(3+x)$

Step-by-step explanation:

a) $x^2+2x$

When factoring a binomial (a polynomial with two terms), what we will be looking for are the terms that are shared between them.

In this problem, it can be seen that both of these terms have and x. This means that we can factor it out to get

$x(x+2)$

b) $2x^2-6x$

What are the common terms here?

It can be seen that each of these share a 2x, so our factored form would be

$2x(x-3)$

c) $15x-10x^3$

What about this one?

The common factor of this one is 5x, so our factored form would be

$5x(3-2x^2)$

d) $9x^2+3x^3$

The common factor of this one is $3x^2$ , so our factored form would be

$3x^2(3+x)$

6 0

4 years ago

Over what interval is the function differentiable? Y=3/2(x-1)

jolli1 [7]

Answer-

The interval where the function is diffrentiable is

$[-\infty,1)\ \bigcup\ (1,\infty]$

Solution-

The given expression is,

$y=\dfrac{3}{2(x-1)}$

The function will be differentiable where it is continuous and it will not be differentiable, where the function is not continuous.

The function continuous everywhere except at x = 1, because

$\Rightarrow 2(x-1)=0\\\\\Rightarrow x-1=0\\\\\Rightarrow x=1$

at x = 1, its limit does not exist.

Therefore, apart from x=1, this function is differentiable everywhere. The interval will be

$[-\infty,1)\ \bigcup\ (1,\infty]$

3 0

3 years ago

The length of a rectangle is four times its width.

Anna11 [10]

Answer:

Step-by-step explanation:

Area of a rectangle is given by:

....[1]

where

l is the length

w is the width of the rectangle respectively.

As per the statement:

the length of a rectangle is four times its width.

⇒

It is also given that: area of rectangle is 1024 cm square

Substitute the given values in [1] we have;

⇒

Divide both sides by 4 we have;

Taking square root both sides we have;

Therefore, the width of the rectangle is, 16 cm

4 0

4 years ago

What is the value of 2^-4

nignag [31]

The answer for 2^-4 is 1/16

4 0

4 years ago

Read 2 more answers