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Y_Kistochka [10]
2 years ago
12

Each Tuesday, Ryan Airlines reduces its one-way ticket from Fort Wayne to Chicago from $125 to $40. To receive this special $40

price, the customer must buy a round-trip ticket. Ryan has a nonrefundable 25% penalty fare for cancellation; it estimates that about nine-tenths of 1% will cancel their reservations. The airline also estimates this special price will cause a passenger traffic increase from 400 to 900. Ryan expects revenue for the year to be 55.4% higher than the previous year. Last year, Ryan's sales were $482,000. To receive the special rate, Janice Miller bought two round-trip tickets. On other airlines, Janice has paid $100 round trip (with no cancella- tion penalty). Calculate the following: LU 6-2(2) a. Percent discount Ryan is offering. b. Percent passenger travel will increase. c. Sales for new year. d. Janice's loss if she cancels one round-trip flight. e. Approximately how many more cancellations can Ryan Airlines expect (after Janice's cancellation)? 6_95 A local Dunlrinn
Mathematics
1 answer:
PolarNik [594]2 years ago
8 0

The percentage discount Ryan is offering is 34%.

The percentage increase in passenger travel is 125%.

The sales for the new year is $147,510.

Janice's loss if she cancels one round trip is $41.25.

The number of cancellations that can be expected is 7.

<h3>What is the discount Ryan is offering?</h3>

Percent discount = (change in price of round trip / price of a round trip before discount) x 100

  • Price of a round trip before discount = $125 x 2 = $250
  • Price of a round trip after discount = $125 + $40 = $165
  • Change in price of round trip = $250 - $165 = $85

Percent discount = ($85 / $250) X 100 = 34%

<h3>What is the percentage increase in passenger travel?</h3>

Percent increase = (change in number of passengers / initial passengers) x 100

(900 - 400) / 400 x 100 = 125%

<h3>What is the sales for the new year?</h3>

The sales for the new year = penalty fare for those who cancelled + total revenue from those who do not cancel.

Penalty fare for those who cancelled = 9/10 ( 0.01 x 900) = 8 people would cancel

25/100 x 8 x $165 = $330

Total revenue from those who do not cancel = (900 - 8) X $165 = $147,180

The sales for the new year = $147,180 + $330 = $147,510

<h3>What is Janice loss if she cancels one round trip?</h3>

Loss = 25/100 x $165 = $41.25

<h3>How many more cancellations can be expected?</h3>

8 - 1 = 7

To learn more about how to calculate discounts, please check: brainly.com/question/26061308

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A random sample of n = 40 observations from a quantitative population produced a mean x = 2.2 and a standard deviation s = 0.29.
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Answer:

t=\frac{2.2-2.1}{\frac{0.29}{\sqrt{40}}}=2.18    

df=n-1=40-1=39  

Since is a one side test the p value would be:  

p_v =P(t_{(39)}>2.18)=0.0177  

If we compare the p value and the significance level given \alpha=0.05 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis, and then the population mes seems to be higher than 2.1 at 5% of significance

Step-by-step explanation:

Data given and notation  

\bar X=2.2 represent the sample mean

s=0.29 represent the sample standard deviation

n=40 sample size  

\mu_o =2.1 represent the value that we want to test

\alpha=0.05 represent the significance level for the hypothesis test.  

t would represent the statistic (variable of interest)  

p_v represent the p value for the test (variable of interest)  

State the null and alternative hypotheses.  

We need to conduct a hypothesis in order to check if the mean is higher than 2,1, the system of hypothesis would be:  

Null hypothesis:\mu \leq 2.1  

Alternative hypothesis:\mu > 2.1  

If we analyze the size for the sample is > 30 but we don't know the population deviation so is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:  

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}  (1)  

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

Calculate the statistic

We can replace in formula (1) the info given like this:  

t=\frac{2.2-2.1}{\frac{0.29}{\sqrt{40}}}=2.18    

P-value

The first step is calculate the degrees of freedom, on this case:  

df=n-1=40-1=39  

Since is a one side test the p value would be:  

p_v =P(t_{(39)}>2.18)=0.0177  

Conclusion  

If we compare the p value and the significance level given \alpha=0.05 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis, and then the population mes seems to be higher than 2.1 at 5% of significance

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Answer:

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