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Nastasia [14]
3 years ago
15

Brook says there are 49 days until july 4 there are 7 days in a week in how many weeks will it be until july 4

Mathematics
2 answers:
ASHA 777 [7]3 years ago
7 0
Because 49 can be divided by 7 just divide the 49 days until july 4th by 7 in order to get 7 weeks left because you used the 7 in a week to divide into the amount of days left
Alik [6]3 years ago
6 0
Easy, 7.......................
You might be interested in
Boxes that are 12 inches tall are being stacked next to boxes that are 18 inches tall. What is the shortest height qt which the
motikmotik

Answer:

The shortest height is 36 inches

Step-by-step explanation:

Here in this question, we want to know the shortest height with which boxes of 12 inches tall staked will be the same height with which boxes of 18 inches staked beside it

This is a question that has to do with multiples; In other words, we are simply looking for the lowest common multiple of 12 and 18;

The multiples of both are as follows;

12 - 12, 24,36,48,60•••••

18-18,36,54,72••••••

We can see that at the point 36, both have their first multiple match

So we can say that the lowest common multiple of 18 and 12 is 36

3 0
3 years ago
In the following problem, check that it is appropriate to use the normal approximation to the binomial. Then use the normal dist
WARRIOR [948]

Answer:

(a) The probability that more than 180 will take your free sample is 0.1056.

(b) The probability that fewer than 200 will take your free sample is 0.9997.

(c) The probability that a customer will take a free sample and buy the product is 0.2184.

(d) The probability that between 60 and 80 customers will take the free sample and buy the product is 0.8005.

Step-by-step explanation:

We are given that about 56% of all customers will take free samples. Furthermore, of those who take the free samples, about 39% will buy what they have sampled.

The day you were offering free samples, 303 customers passed by your counter.

Firstly, we will check that it is appropriate to use the normal approximation to the binomial, that is;

Is np > 5  and  n(1-p) > 5

In our question, n = sample of customers = 303

                          p = probability that customers will take free sample = 56%

So, np = 303 \times 0.56 = 169.68 > 5

     n(1-p) = 303 \times (1-0.56) = 133.32 > 5

Since, both conditions are satisfied so it is appropriate to use the normal approximation to the binomial.

Now, mean of the normal distribution is given by;

        Mean, \mu = n \times p = 169.68

Also, the standard deviation of the normal distribution is given by;

       Standard deviation, \sigma = \sqrt{n \times p \times (1-p)}

                                            = \sqrt{303 \times 0.56 \times (1-0.56)} = 8.64

Let X = Number of people who will take your free sample

The z score probability distribution for normal distribution is given by;

                           Z  =  \frac{X-\mu}{\sigma}  ~ N(0,1)

(a) The probability that more than 180 will take your free sample is given by = P(X > 180) = P(X > 180.5)     {Using continuity correction}

        P(X > 180.5) = P( \frac{X-\mu}{\sigma} > \frac{180.5-169.68}{8.64} ) = P(Z > 1.25) = 1 - P(Z < 1.25)

                                                                   = 1 - 0.8944 = <u>0.1056</u>

(b) The probability that fewer than 200 will take your free sample is given by = P(X < 200) = P(X < 199.5)     {Using continuity correction}

        P(X < 199.5) = P( \frac{X-\mu}{\sigma} < \frac{199.5-169.68}{8.64} ) = P(Z < 3.45) = <u>0.9997</u>

(c) We are given in the question that of those who take the free samples, about 39% will buy what they have sampled, this means that we have;

     P(Buy the product / taken a free sample) = 0.39

So, Probability(customer will take a free sample and buy the product) = P(customer take a free sample) \times P(Buy the product / taken a free sample)

     = 0.56 \times 0.39 = <u>0.2184</u>

(d) Now our mean and standard deviation will get changed because the probability of success now is p = 0.2184 but n is same as 303.

So, Mean, \mu = n \times p = 303 \times 0.2184 = 66.18

Standard deviation, \sigma = \sqrt{n \times p \times (1-p)}

                                    = \sqrt{303 \times 0.2184 \times (1-0.2184)} = 7.192

Now, the probability that between 60 and 80 customers will take the free sample and buy the product is given by = P(60 < X < 80) = P(59.5 < X < 80.5)         {Using continuity correction}

     P(59.5 < X < 80.5) = P(X < 80.5) - P(X \leq 59.5)

     P(X < 80.5) = P( \frac{X-\mu}{\sigma} < \frac{80.5-66.18}{7.192} ) = P(Z < 1.99) = 0.9767

     P(X \leq 59.5) = P( \frac{X-\mu}{\sigma} \leq \frac{59.5-66.18}{7.192} ) = P(Z \leq -0.93) = 1 - P(Z < 0.93)

                                                            = 1 - 0.8238 = 0.1762

Therefore, P(59.5 < X < 80.5) = 0.9767- 0.1762 = <u>0.8005.</u>

4 0
3 years ago
a bag of marbles contains 8 red marbles, 4 blue marbles, and 5 white marbles. tom picks a marble at random. is it more likely th
iVinArrow [24]

Answer:

It is more likely of a diffrent color.

Step-by-step explanation:

8 to 9

Red to other.

8 0
3 years ago
Pleeaaassseeeees help,
sattari [20]

Hey there!

Since you probably have better things to do, your answer would be A: π(3)²

To back up my answer, the formula to find the area of a circle is π · R² where R = Radius. In that formula then, you just plug everything in. Since the radius is 3, you would put 3 into the "( )". Finally, just plug the rest of the equation in!

<em>I'm open to any question or comment!</em>

<em>God Bless!</em>

<em>-X8lue83rryX</em>

5 0
3 years ago
Under her cell phone plan, Rajani pays a flat cost of $65 per month and $5
riadik2000 [5.3K]
If she wants to only use 85 a month then doing the math it would be 85-65=20 divided by 5 equals 4 so she would get 4 gigabytes while staying within her budget :)

Brainiest please
3 0
3 years ago
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