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3 years ago

Brook says there are 49 days until july 4 there are 7 days in a week in how many weeks will it be until july 4

2 answers:

7 0

Because 49 can be divided by 7 just divide the 49 days until july 4th by 7 in order to get 7 weeks left because you used the 7 in a week to divide into the amount of days left

Alik [6]3 years ago

6 0

Easy, 7.......................

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The system of equations relates the distance, y,

Monica [59]

Is it 7.1 or something I don’t know for sure

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3 years ago

Jillian's puppy weighed 16 pounds at the age of 2 months. It weighed 60 pounds at the age of 8 months. What is the percent chang

mel-nik [20]

Answer:the percent change in the puppy's weight= 275%

Step-by-step explanation:

Jillian's puppy Weight at 2 months =16 pounds

Jillian's puppy Weight at 8 months =60 pounds

percent change in the puppy's weight= change in weight / Old weight x 100

(60 pounds -16pounds ) / 16 x 100

44/16 x 100 = 275%

6 0

2 years ago

The circumference of a circle can be found using the

hichkok12 [17]

Answer:

It is the second one

Step-by-step explanation:

1st option does not include the number 2 from the equation above,

and 3 and 4, you do not have to divide anywhere in the equation, so those are no possibly correct.

6 0

3 years ago

Use the first five terms of the trigonometric series to approximate the value of <img src="https://tex.z-dn.net/?f=sin%5Cfrac%7B

Schach [20]

Answer:b

Step-by-step explanation:

3 0

3 years ago

Select the pair of slopes that are the slopes of perpendicular lines.

agasfer [191]

<h3> $\frac{3}{4}\ and\ \frac{-4}{3}$ are the slopes of perpendicular lines</h3>

Solution:

We know that,

Product of slope of a line and slope of line perpendicular to it is always equal to -1

Option 1

$\frac{1}{2}\ and\ 2$

$Product = \frac{1}{2} \times 2 = 1$

Thus, these are not the slopes of perpendicular lines

Option 2

$\frac{3}{4}\ and\ \frac{-4}{3}\\\\Product = \frac{3}{4} \times \frac{-4}{3}\\\\Product = -1$

This option satisfies the slopes of perpendicular lines

Option 3

$\frac{-2}{5}\ and\ \frac{-5}{2}\\\\Product = \frac{-2}{5} \times \frac{-5}{2} = 1$

Thus, these are not the slopes of perpendicular lines

Option 4

2 and 2

Product = 2 x 2 = 4

Thus, these are not the slopes of perpendicular lines

7 0

3 years ago