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2 years ago

Brook says there are 49 days until july 4 there are 7 days in a week in how many weeks will it be until july 4

2 answers:

7 0

Because 49 can be divided by 7 just divide the 49 days until july 4th by 7 in order to get 7 weeks left because you used the 7 in a week to divide into the amount of days left

Alik [6]2 years ago

6 0

Easy, 7.......................

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The cost per purse is $17 each to make, and she sells them for $35 each. This Saturday, she is renting a booth at a craft fair f

klasskru [66]

T = Total income

N = Number of purses

35N = the selling price of each purse

17N = Cost of each purse

T = 35*N - 17*N - 75

T = 18N - 75

If she wants here total income to be 350 dollars, it will take

T = 350 ; N = unknown.

350 = 18N - 75 Add 75 to both sides.

350 + 75 = 18N

425 = 18N

Rounded N = 24 <<<< Answer. The actually number is 23.611 but you can't sell 0.611 of a purse.

6 0

2 years ago

A geometric sequence has these properties: a^1=2

grin007 [14]

The third term of the sequence is 20

3 0

2 years ago

If it takes Tim 20 minutes to bike 6 miles, how many minutes will it take him to bike 144 miles?

kari74 [83]

Answer:

144/6 = 24

24 x 20 = 480

480 is the answer

3 0

2 years ago

Read 2 more answers

One paperback book costs $7. How many books can be bought for $133?

mariarad [96]

Answer:

the answer is 19 book

Step-by-step explanation:

133 divided by 7

5 0

2 years ago

Read 2 more answers

Consider the differential equation <img src="https://tex.z-dn.net/?f=%20x%5E%7B2%7D%20%20%5Cfrac%7Bdy%7D%7Bdx%7D%20%3D6%20y%5E%7

Nutka1998 [239]

As a Bernoulli equation:

$x^2\dfrac{\mathrm dy}{\mathrm dx}=6y^2+6xy\iff x^2y^{-2}\dfrac{\mathrm dy}{\mathrm dx}-6xy^{-1}=6$

Let $z=y^{-1}\implies\dfrac{\mathrm dz}{\mathrm dx}=-y^{-2}\dfrac{\mathrm dy}{\mathrm dx}$ . The ODE becomes

$-x^2\dfrac{\mathrm dz}{\mathrm dx}-6xz=6$
$x^6\dfrac{\mathrm dz}{\mathrm dx}+6x^5z=-6x^4$
$\dfrac{\mathrm d}{\mathrm dx}[x^6z]=-6x^4$
$x^6z=-6\displaystyle\int x^4\,\mathrm dx$
$x^6z=-\dfrac65x^5+C$
$z=-\dfrac6{5x}+\dfrac C{x^6}$
$y^{-1}=-\dfrac6{5x}+\dfrac C{x^6}$
$y=\dfrac1{\frac C{x^6}-\frac6{5x}}$
$y=\dfrac{5x^6}{C-6x^5}$

With $y(3)=6$ , we get

$6=\dfrac{5(3)^6}{C-6(3)^5}\implies C=\dfrac{4131}2$

so the solution is

$y=\dfrac{5x^6}{\frac{4131}2-6x^5}=\dfrac{10x^6}{4131-12x^5}$

which is valid as long as the denominator is not zero, which is the case for all $x\neq\sqrt[5]{\dfrac{4131}{12}}$ .

8 0

2 years ago