How to solve 3(6x+2x)=8(5x+6)-4x

1 answer:

6 0

First, you are going to distribute the 3 into the (6x+2x) and the 8 into the (5x+6). After that, the parenthesis should be gone. Then, move all the x values to one side, and the constants to the other. Then, solve as you normally would.

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How do I solve ln(x) + ln(5) = 2 ?

motikmotik

we'll use the same log cancellation rule, since this is pretty much the same thing as the other, just recall that ln = logₑ.

$\bf \textit{Logarithm Cancellation Rules}
\\\\
log_a a^x = x\qquad \qquad \stackrel{\stackrel{\textit{we'll use this one}}{\downarrow }}{a^{log_a x}=x}
\\\\\\
\textit{logarithm of factors}
\\\\
log_a(xy)\implies log_a(x)+log_a(y)
\\\\[-0.35em]
\rule{34em}{0.25pt}\\\\
ln(x)+ln(5)=2\implies ln(x\cdot 5)=2\implies log_e(5x)=2
\\\\\\
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$\bf \\\\[-0.35em]
\rule{34em}{0.25pt}\\\\
ln(x)-ln(5)=2\implies ln\left( \cfrac{x}{5} \right)=2\implies log_e\left( \cfrac{x}{5} \right)=2\implies e^{log_e\left( \frac{x}{5} \right)}=e^2
\\\\\\
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Simplify the following expression.<br><br> (2x 2 y 4)3

shusha [124]

<span>(2x^2 y^4)3
= 2^3 x^6 y^12
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hope it helps</span>

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Step-by-step explanation:

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