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2 years ago

8

45.348 to two decimal places

2 answers:

Lisa [10]2 years ago

8 0

Answer:

45.35

Step-by-step explanation:

Because there are 3 numbers to the right of the decimal point, this number has 3 decimal places. This question wants you to alter the number so that it has only 2 numbers to the right of the decimal. You can't just totally ignore the numbers you want to eliminate, so rounding rules need to be applied.

First, identify the number in the second decimal place position. If the number to the right of this position (the third decimal position) is in the range of 5 - 9, you must add 1 to the second decimal place value. Then, you can drop the numbers after the second decimal place. If the number to the right is 0 - 4, you can simply drop it the value and all the other values to the right.

In this case, the second decimal place has a value of 4. The number to the right is 8. Because 8 is within the 5 - 9 range, add 1 to 4 to get a new decimal value of 5. Finally, drop all the numbers to the right of the new second decimal place value. This leaves you with your answer: 45.35.

gayaneshka [121]2 years ago

3 0

45.35 is your answer once you round it

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Each statement describes a transformation of the graph of y = x. Which statement correctly describes the graph of y = x + 7? A.

rosijanka [135]

<h3>Answer: choice A, graph is moved 7 units up</h3>

The plus 7 at the end will shift the graph 7 units up. Replace y with f(x).

Then we have g(x) = f(x) + 7. Adding 7 to y = f(x) will increase the y value by 7.

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3 years ago

50 is 50% of what number? Plz show work in explanation thanks. Again im in middle school i musta misclicked high school instead

erastovalidia [21]

100

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6 0

3 years ago

Simplify the expression.

Anna71 [15]

Since we have a cubic root, we're interested in factoring cubes inside the root, so that we can take them out. If we factor 648, we have

$648=2^3\times 3^4=2^3\times 3^3\times 3 = (2\times 3)^3\times 3 = 3\times 6^3$

So, we have

$3x\sqrt[3]{648 x^4 y^8} = \sqrt[3]{3\times 6^3\cdot x^3\cdot x \cdot y^6\cdot y^2}=3x\cdot 6\cdot x\cdot y^2\sqrt[3]{3\cdot x\cdot y^2}$

And the result simplifies to

$18x^2y^2\sqrt[3]{3xy^2}$

5 0

3 years ago

On a map, 1 inch equals 20 miles. Two cities are 7 inches apart on the map. What is the actual distance between the cities?

MrRa [10]

Answer:

140 miles

Step-by-step explanation:

1 times 20 (1 inch=20 miles)

2 times 20 (2 inches=40 miles)

3 times 20 (3 inches=60 miles)

4 times 20 (4 inches=80 miles)

5 times 20 (5 inches=100 miles)

6 times 20 (6 inches=120 miles)

7 times 20 (7 inches=140 miles)

Hope this helped!! :)

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5 0

2 years ago

Simplify completely sqrt of 20Y^8

brilliants [131]

Answer:

Final answer is $2y^4 \sqrt{5}$ .

Step-by-step explanation:

Given expression is $\sqrt{20y^8}$ .

Now we need to smplify the given expression $\sqrt{20y^8}$ .

So begin with factoring 20 into two parts so that one part is perfect square number.

$\sqrt{20y^8}$

$=\sqrt{4 \times 5y^8}$

$=\sqrt{4 y^8} \times \sqrt{5}$

$=2y^4 \times \sqrt{5}$

Hence final answer is $2y^4 \sqrt{5}$ .

3 0

3 years ago