Note: Consider the side of first triangle is TQ instead of TA.
Given:
Triangles TQM and TPN which share vertex T.
To find:
The theorem which shows that 
.
Solution:
In triangle TQM and TPN,
[Given]
[Given]
[Given]
Since two sides and their including angle are congruent in both triangles, therefore both triangles are congruent by SAS postulate.
[SAS]
Therefore, the correct option is C.
Answer:
⣿⣯⣿⣟⣟⡼⣿⡼⡿⣷⣿⣿⣿⠽⡟⢋⣿⣿⠘⣼⣷⡟⠻⡿⣷⡼⣝⡿⡾⣿ ⣿⣿⣿⣿⢁⣵⡇⡟⠀⣿⣿⣿⠇⠀⡇⣴⣿⣿⣧⣿⣿⡇⠀⢣⣿⣷⣀⡏⢻⣿ ⣿⣿⠿⣿⣿⣿⠷⠁⠀⠛⠛⠋⠀⠂⠹⠿⠿⠿⠿⠿⠉⠁⠀⠘⠛⠛⠛⠃⢸⣯ ⣿⡇⠀⣄⣀⣀⣈⣁⠈⠉⠃⠀⠀⠀⠀⠀⠀⠀⠀⠠⠎⠈⠀⣀⣁⣀⣀⡠⠈⠉ ⣿⣯⣽⡿⢟⡿⠿⠛⠛⠿⣶⣄⠀⠀⠀⠀⠀⠀⠈⢠⣴⣾⠛⠛⠿⠻⠛⠿⣷⣶ ⣿⣿⣿⠀⠀⠀⣿⡿⣶⣿⣫⠉⠀⠀⠀⠀⠀⠀⠀⠈⠰⣿⠿⠾⣿⡇⠀⠀⢺⣿ ⣿⣿⠻⡀⠀⠀⠙⠏⠒⡻⠃⠀⠀⠀⠀⣀⠀⠀⠀⠀⠀⠐⡓⢚⠟⠁⠀⠀⡾⢫ ⣿⣿⠀⠀⡀⠀⠀⡈⣉⡀⡠⣐⣅⣽⣺⣿⣯⡡⣴⣴⣔⣠⣀⣀⡀⢀⡀⡀⠀⣸ ⣿⣿⣷⣿⣟⣿⡿⣿⣿⣿⣿⣿⣿⣿⣿⣿⣿⣿⣿⣿⣿⣿⣿⣿⣿⣿⢻⢾⣷⣿ ⣿⣿⣟⠫⡾⠟⠫⢾⠯⡻⢟⡽⢶⢿⣿⣿⡛⠕⠎⠻⠝⠪⢖⠝⠟⢫⠾⠜⢿⣿ ⣿⣿⣿⠉⠀⠀⠀⠀⠈⠀⠀⠀⠀⣰⣋⣀⣈⣢⠀⠀⠀⠀⠀⠀⠀⠀⠀⣐⢸⣿ ⣿⣿⣿⣆⠀⠀⠀⠀⠀⠀⠀⠀⢰⣿⣿⣿⣿⣿⣧⠀⠀⠀⠀⠀⠀⠀⠀⢀⣾⣿ ⣿⣿⣿⣿⣦⡔⠀⠀⠀⠀⠀⠀⢻⣿⡿⣿⣿⢽⣿⠀⠀⠀⠀⠀⠀⠀⣠⣾⣿⣿ ⣿⣿⣿⣿⣿⣿⣶⣤⣀⠀⠀⠀⠘⠛⢅⣙⣙⠿⠉⠀⠀⠀⢀⣠⣴⣿⣿⣿⣿⣿ ⣿⣿⣿⣿⣿⣿⣿⣿⣿⣿⣶⣤⣄⣅⠀⠓⠀⠀⣀⣠⣴⣺⣿⣿⣿⣿⣿⣿⣿⣿
Step-by-step explanation:
i nu speak that language
Answer:
f(x) = -4x + 80
Step-by-step explanation:
You are given two points,
(5, 60) and (10, 40)
in order to get the equation, let's use the form slope-intercept form
m = (y1 - y2) / (x1 - x2)
m = (60 - 40) / (5 - 10)
m = 20/-5
m = -4
Get the x intercept
y = mx + b
60 = (-4)(5) + b
b = 60+20
b = 80
so the equation is
y = -4x + 80
f(x) = -4x + 80
When you graph the three lines, the first two overlap. The third is parallel to those two.
