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2 years ago

A shed has dimensions of 12m in length and 5 m in width. Both the length and

Mathematics

2 answers:

Andrew [12]2 years ago

5 0

lol Looks like someone has the same math assignment as me

BlackZzzverrR [31]2 years ago

3 0

Answer:

Length = 24

Step-by-step explanation:

It says, " Both the length and width are increased by the same amount..." this means that both 12m and 5m were increased. So 12 + 12 = 24 and 5 + 5 = 10.

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Explain how you could convert 152 cups into gallons.

Mila [183]

Answer: There are 16 cups in every gallon so we could divide 152 by 16 and get our number of gallons which would give us 9.63 or a little over 9 and a half gallons.

Step-by-step explanation:

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3 years ago

Is. 8.250 greater. than. 8.25

Valentin [98]

Answer:no

There both the same because just the differnce is the last number which is zero.

Step-by-step explanation:

All you got to do is find the answer and thats all

Plzz mark brainlest and thank me

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3 years ago

Read 2 more answers

The answers are either: 12, 2, 8, or 10 please helppp

blsea [12.9K]

Answer: 10 I believe

Step-by-step explanation:

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3 years ago

Solve the following question

White raven [17]

Answer:

g) $u^{4}\cdot v^{-1}\cdot z^{3}$ , h) $\frac{(x+4)\cdot (x+2)}{3\cdot (x-5)}$

Step-by-step explanation:

We proceed to solve each equation by algebraic means:

g) $\frac{u^{5}\cdot v}{z}\div \frac{u\cdot v^{2}}{z^{4}}$

1) $\frac{u^{5}\cdot v}{z}\div \frac{u\cdot v^{2}}{z^{4}}$ Given

2) $\frac{\frac{u^{5}\cdot v}{z} }{\frac{u\cdot v^{2}}{z^{4}} }$ Definition of division

3) $\frac{u^{5}\cdot v\cdot z^{4}}{u\cdot v^{2}\cdot z}$ $\frac{\frac{a}{b} }{\frac{c}{d} } = \frac{a\cdot d}{b\cdot c}$

4) $\left(\frac{u^{5}}{u} \right)\cdot \left(\frac{v}{v^{2}} \right)\cdot \left(\frac{z^{4}}{z} \right)$ Associative property

5) $u^{4}\cdot v^{-1}\cdot z^{3}$ $\frac{a^{m}}{a^{n}} = a^{m-n}$ /Result

h) $\frac{x^{2}-16}{x^{2}-10\cdot x + 25} \div \frac{3\cdot x - 12}{x^{2}-3\cdot x -10}$

1) $\frac{x^{2}-16}{x^{2}-10\cdot x + 25} \div \frac{3\cdot x - 12}{x^{2}-3\cdot x -10}$ Given

2) $\frac{\frac{x^{2}-16}{x^{2}-10\cdot x+25} }{\frac{3\cdot x - 12}{x^{2}-3\cdot x - 10} }$ Definition of division

3) $\frac{(x^{2}-16)\cdot (x^{2}-3\cdot x -10)}{(x^{2}-10\cdot x + 25)\cdot (3\cdot x - 12)}$ $\frac{\frac{a}{b} }{\frac{c}{d} } = \frac{a\cdot d}{b\cdot c}$

4) $\frac{(x+4)\cdot (x-4)\cdot (x-5)\cdot (x+2)}{3\cdot (x-5)^{2}\cdot (x-4) }$ Factorization/Distributive property

5) $\left(\frac{1}{3} \right)\cdot (x+4)\cdot (x+2)\cdot \left(\frac{x-4}{x-4} \right)\cdot \left[\frac{x-5}{(x-5)^{2}} \right]$ Modulative and commutative properties/Associative property

6) $\frac{(x+4)\cdot (x+2)}{3\cdot (x-5)}$ $\frac{a^{m}}{a^{n}} = a^{m-n}$ / $\frac{a}{b}\times \frac{c}{d} = \frac{a\cdot c}{b\cdot d}$ /Definition of division/Result

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3 years ago

What is the measure of BC⏜ ? Enter your answer in the box. ° Circle with inscribed angle B D C. Angle B D C is 65 degrees.

Zigmanuir [339]

Answer:

Minor arc BC - 130° (arc at which inscribed angle is subtended)

The major arc BC - 230°

Step-by-step explanation:

Angle BDC is inscribed angle subtended on the arc BC.

The measure of the angle BDC is 65°.

The Central Angle Theorem states that the central angle from two chosen points B and C on the circle is always twice the inscribed angle from those two points.

By the central angle theorem, the measure of central angle BOC (O is the center of the circle) has the measure of

$2\cdot 65^{\circ}=130^{\circ}$

Hence, the minor arc BC has the same measure as the central angle BOC that is 130°.

The major arc BC has the measure

$360^{\circ}-130^{\circ}=230^{\circ}$

6 0

3 years ago

Read 2 more answers