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olga2289 [7]
3 years ago
8

What are the first three terms of the sequence: a1 = 3 and an = 2(an -1)^2?. . a. 2, 8, 18. . b. 3, 18, 648. . c. 3, 32, 50. . d

. 2, 6, 12, 24. .
Mathematics
1 answer:
AlexFokin [52]3 years ago
7 0
The first term of the sequence is already given to be 3. Use this value to obtain the second term.
                                     a2 = 2(a1)^2 = 2(3)² = 18
Use the value of the second term to get the third term through the equation,
                                     a3 = 2(a2)² = 2(18)² = 648
Thus, the answer to this item is letter B. 
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149 cars are waiting to take a ferry across the channel. Each ferry can only hold 18 cars. How many cars will be on the last fer
balandron [24]

149 \div 18 = x
8r5 = x
There will be 9 trips the ferry makes and on the last trip there will be 5 cars on the ferry.

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the cost of a cell phone varies directly with the number of minutes it uses.if it costs $73.25 to talk for 180 minutes , what is
Vladimir79 [104]

Answer:I believe 786.34

Step-by-step explanation:

You divide 180 by 73.25 which is 2.46, then multiply this number by your 320 minutes to get the answer

4 0
3 years ago
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What is the simplified form of the following expression?
Amanda [17]
You have sqrt(8), sqrt(18), and sqrt(2).
You need to simplify the radicals.
sqrt(2) is already simplified.
For both sqrt(8) and sqrt(18), you need to factor out the greatest perfect square.

8 = 4 * 2
You can take the square root of 4 and put it outside the root.

18 = 9 * 2
You can take the square root of 9 and put it outside the root.

5 \sqrt{8} - \sqrt{18} -2 \sqrt{2} =

= 5 \sqrt{4 \times 2} - \sqrt{9 \times 2} -2 \sqrt{2}

= 5 \times 2\sqrt{2} - 3 \sqrt{2} -2 \sqrt{2}

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8 0
3 years ago
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What are the restrictions for a? 2a^2+a-15/5a^2+16a+3
koban [17]

ANSWER


The restrictions are

a\ne -3,a\ne -\frac{1}{5}


EXPLANATION


We were given the rational function,


\frac{2a^2+a-15}{5a^2+16a+3}


The function is defined for all values of a, except



5a^2+16a+3=0


This has become a quadratic trinomial, so we need to split the middle term.


We do that by multiplying the coefficient of x^2 which is 5 by the constant term which is 3. This gives us 15.


The factors of 15 that adds up to 16 are 1 and 15.


We use these factors to split the middle term.




5a^2+15a+a+3=0


We now factor to get,


5a(a+3)+1(a+3)=0


We factor further to get,


(a+3)(5a+1)=0



This implies that,


(a+3)=0,(5a+1)=0


This gives


a=-3,a=-\frac{1}{5}


These are the restrictions.





8 0
3 years ago
Look at the which statement would prove that lines a and b are parallel ?
slega [8]
It is between the first two I believe it is the first one I am not absolutly sure though
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