1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
daser333 [38]
3 years ago
9

Can someone please help me I don’t understand this. I keep getting it wrong

Mathematics
1 answer:
kicyunya [14]3 years ago
7 0

Answer:

K- (-8, -2)

L- (2, -2)

J- (-8, -5)

M- (2, -5)

Step-by-step explanation:

Vertices refer to the points where the lines connect, or corners. In this problem they're represented by K, L, J, and M.

The current coordinates are-

K- (-8, -4)

L- (2, -4)

J- (-8, -7)

M- (2, -7)

Since the Y coordinate refers to vertical distance and the X coordinate refers to horizontal distance, translating them two units up would involve adding positive two to each y coordinate.

Therefore the new coordinates would be

K- (-8, -2)

L- (2, -2)

J- (-8, -5)

M- (2, -5)

Hope this was helpful! Sorry if I messed up askdjasjk

You might be interested in
Two numbers totals -14, and their difference is 6. Find the two numbers​
natita [175]

Answer:

The two numbers are -4 and -10.

Step-by-step explanation:

x+y=-14

x-y=6

----------

2x=-8

x=-8/2

x=-4

-4+y=-14

y=-14-(-4)=-14+4=-10

x=-4, y=-10.

4 0
3 years ago
What are the zeros of the quadratic function f(x) = 2x2 – 10x – 3?
Ipatiy [6.2K]

Answer:

x = \frac{ 5 \ + \ \sqrt{31}}{2} \ , \ x = \frac{ 5 \ - \ \sqrt{31}}{2}

Step-by-step explanation:

2x^2 - 10x - 3 = 0 \\\\a = 2 \ , b = - 10 \ , \ c =  - 3 \\\\x = \frac{-b^2\  \pm \ \sqrt{b^2 - 4ac}}{2a}\\\\x = \frac{10 \ \pm \sqrt{(-10)^2 - ( 4 \times 2 \times -3)} }{2 \times 2}\\\\x = \frac{10 \ \pm \sqrt{(100 - ( -24 )} }{4}\\\\x = \frac{10 \ \pm \sqrt{(100 + 24 } }{4}\\\\x = \frac{ 10 \ \pm \sqrt{124}}{4}\\\\x = \frac{ 10 \ \pm \sqrt{4 \times 31}}{4}\\\\x = \frac{ 10 \ \pm \sqrt{2^2 \times 31}}{4}\\\\x = \frac{ 10 \ \pm2 \sqrt{31}}{4}\\\\x = \frac{ 5 \ \pm\sqrt{31}}{2}\\\\

x = \frac{ 5 \ + \ \sqrt{31}}{2} \ , \ x = \frac{ 5 \ - \ \sqrt{31}}{2}

3 0
2 years ago
A student spends $48 on school supplies at a store where sales tax is 7%. What is the total cost of the supplies?
Advocard [28]

Answer:

The answer is 51.36 so just add 48 plus 7%

Step-by-step explanation:

5 0
2 years ago
Read 2 more answers
Find the exact value of tan A in simplest radical form.<br> PLEASE HELP
Tju [1.3M]

Answer:

\tan(A)  =  \frac{opp}{adj}  \\  \tan(A)  =  \frac{ \sqrt{72} }{3}  \\  \tan(A)  =  \frac{ \sqrt{36 \times 2} }{3}  \\  \tan(A)  =  \frac{6 \sqrt{2} }{3}  \\  \tan(A)  = 2 \sqrt{2}

3 0
2 years ago
A company orders 25 boxed lunches from a deli for $185. If each boxed lunch costs the same amount, what is the unit cost of each
guapka [62]

Answer:

7.40

Step-by-step explanation:

Divide 185 by 25 to get unit rate

7 0
3 years ago
Other questions:
  • I thought of a number, multiplied it by 2 1/2, divided the result by 1 1/5, subtracted 7/18 from it, and got 1 5/6. What was my
    6·1 answer
  • 2. Mr. Nelson bought a car for $20,000 with a 5% interest rate.
    15·1 answer
  • Tammy ran for president of the chess club and she received 27 votes they were 45 members in the club what percentage of the club
    8·1 answer
  • What is it for both?
    15·1 answer
  • Show that if x,y,z and w are the first four terms of an arithmetic sequence, then x+w-y=z
    12·2 answers
  • The area of a rectangle is represented by 3x^2 + 14x + 8. Factor the area to determine the dimensions of the rectangle.
    5·1 answer
  • Select all the expressions that equal 6^-10
    15·2 answers
  • half of an integer exceeds one _ third of the next integer by unity .Find the integer. please ask fast​
    8·1 answer
  • Las medidas interiores de una piscina portátil cilíndrica son 0.85 m de radio y 0.60 m de altura.
    11·1 answer
  • What decimal is equivalent to 4/100 + 5/10
    5·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!