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max2010maxim [7]
2 years ago
14

Find the exact value of tan A in simplest radical form. PLEASE HELP

Mathematics
1 answer:
Tju [1.3M]2 years ago
3 0

Answer:

\tan(A)  =  \frac{opp}{adj}  \\  \tan(A)  =  \frac{ \sqrt{72} }{3}  \\  \tan(A)  =  \frac{ \sqrt{36 \times 2} }{3}  \\  \tan(A)  =  \frac{6 \sqrt{2} }{3}  \\  \tan(A)  = 2 \sqrt{2}

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HELP ME QUICK PLEASEEEE solve for x: 2/x-2+7/x^2-4=5/x
Anna35 [415]

 

\displaystyle\\\\\frac{2}{x-2}+\frac{7}{x^2-4}=\frac{5}{x}\\\\\frac{^{x+2)}2~~~~~}{x-2}+\frac{7}{(x-2)(x+2)}=\frac{5}{x}\\\\\frac{2(x+2)}{(x-2)(x+2)}+\frac{7}{(x-2)(x+2)}=\frac{5}{x}\\\\\frac{2x+4+7}{x^2-4}=\frac{5}{x}\\\\\frac{2x+11}{x^2-4}=\frac{5}{x}\\\\5(x^2-4)=x(2x+11)\\\\5x^2-20=2x^2+11x\\\\5x^2-2x^2 -11x-20=0


\displaystyle\\3x^2-11x-20=0\\\\x_{1,2}=\frac{-b\pm\sqrt{b^2-4ac}}{2a}=\frac{11\pm\sqrt{121+4\cdot3\cdot20}}{2\cdot3}=\\\\=\frac{11\pm\sqrt{121+240}}{6}=\frac{11\pm\sqrt{361 }}{6}=\frac{11\pm19}{6}\\\\x_1=\frac{11-19}{6}=\frac{-8}{6}\\\\\boxed{\bf x_1=-\frac{4}{3}}\\\\x_2=\frac{11+19}{6}=\frac{30}{6}\\\\\boxed{\bf x_2=5}




3 0
3 years ago
The sum of two numbers is 46. The larger number is two less than three times the smaller number. Find the numbers.‍♀️
Alex787 [66]

Answer:

Smaller number: 12

Larger number: 34

Step-by-step explanation:

Let x represent the smaller number.

Let 3x - 2 represent the larger number (The larger number is two less than three times the smaller number, or x)

x + 3x -2 = 46

   Add 3x + x:

4x - 2 = 46

   Add 2 to both sides:

4x = 46 + 2

   Add 46 + 2:

4x = 48

    Divide both sides by 4:

4x/4 = 48/4

x = 12 is the smaller number

Since 12 is the smaller number, and the sum of the two numbers is 46, than the larger number must be 34.

I hope this helped you. If it did, please consider, rating, pressing thanks and/or giving my answer 'Brainliest.' Have a great day! :)

6 0
2 years ago
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