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max2010maxim [7]
2 years ago
14

Find the exact value of tan A in simplest radical form. PLEASE HELP

Mathematics
1 answer:
Tju [1.3M]2 years ago
3 0

Answer:

\tan(A)  =  \frac{opp}{adj}  \\  \tan(A)  =  \frac{ \sqrt{72} }{3}  \\  \tan(A)  =  \frac{ \sqrt{36 \times 2} }{3}  \\  \tan(A)  =  \frac{6 \sqrt{2} }{3}  \\  \tan(A)  = 2 \sqrt{2}

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According to the rational root theorem, which statement about f(x)= 12x^3-5x^2+6x+9 is true?
scZoUnD [109]
If there are any rational roots, it would be a factor of your constant term (9) divided by a factor of the high-order coefficient (12).
3 0
3 years ago
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Which of the following can be written as the sum of 2 prime numbers
Gnoma [55]

Answer:

b)15

Step-by-step explanation:

13+2=15

Hope that helps

3 0
2 years ago
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What are the critical points for g(θ) = 20θ − 5 tan θ
jarptica [38.1K]

g(θ) = 20θ − 5 tan θ

To find out critical points we take first derivative and set it =0

g(θ) = 20θ − 5 tan θ

g'(θ) = 20 − 5 sec^2(θ)

Now we set derivative =0

20 − 5 sec^2(θ)=0

Subtract 20 from both sides

− 5 sec^2(θ)=0 -20

Divide both sides by 5

sec^2(θ)= 4

Take square root on both sides

sec(θ)= -2  and sec(θ)= +2

sec can be written as 1/cos

so sec(θ)= -2  can be written as cos(θ)= -1/2

Using unit circle the value of θ is \frac{2\pi}{3} and\frac{4\pi}{3}

sec(θ)= 2  can be written as cos(θ)=1/2

Using unit circle the value of θ is \frac{\pi}{3}and\frac{5\pi}{3}

For general solution we add 2npi

So critical points are

\frac{2\pi}{3} + 2n\pi,\frac{4\pi}{3} + 2n\pi , \frac{\pi}{3} + 2n\pi, \frac{5\pi}{3} + 2n\pi


6 0
3 years ago
Tommy is thinking of a number between 800 and 900 He divides it by 4 and there is a remainder of 1 He divides it by 5 and there
Finger [1]

Answer:

841

Step-by-step explanation:

If the number is divided by 4 and the remainder is 1, the last digit must be 1, 3, 5, 7 or 9.

If the number is divided by 5 and the remainder is 1, the last digit must be 6 or 1.

So we already know the last digit must be 1.

The numbers between 800 and 900, with last digit 1, that divided by 6 have a remainder of 1 are:

811, 841, 871

The numbers between 800 and 900, with last digit 1, that divided by 7 have a remainder of 1 is just 841

So Tommy's number is 841.

5 0
3 years ago
What is 999,999,999,999.99 x 500?
sweet [91]

Answer:

5e+14

Step-by-step explanation:

999,999,999,999.99 x 500=5e+14

hope i helped

can u plzz mark me brainlest

6 0
3 years ago
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