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3 years ago

A random sample from the 6th and 7th grade student population was taken to determine which clubs were the most popular.

Mathematics

1 answer:

gtnhenbr [62]3 years ago

6 0

Using the percentage concept, it is found that 25% of 6th graders are involved in the yearbook club.

<h3>What is a percentage?</h3>

The percentage of an amount a over a total amount b is given by a multiplied by 100% and divided by b, that is:

$P = \frac{a}{b} \times 100\%$

In this problem, 10 out of 10 + 24 + 6 = 40 6th graders are involved in the yearbook club, hence the corresponding percentage is given by:

$P = \frac{10}{40} \times 100\% = 25\%$

More can be learned about percentages at brainly.com/question/10491646

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Find the measure of

Bingel [31]

Answer:

I feel like its 75 degrees and also are u in 8th and have u done power quotient and product rule before if so I need help

8 0

3 years ago

How to reduce into simpler terms.?

Sveta_85 [38]

Answer:

The simplest form of the fraction $\frac{45}{100}$ is $\frac{9}{20}$ .

i.e.

$\frac{45}{100}=\frac{9}{20}$

Step-by-step explanation:

Here are some simple observations regarding how to reduce a fraction into simpler terms:

A fraction is reduced to lowest or simplest terms by finding an equivalent fraction in which the numerator and denominator are as small as possible.

In order to reduce a fraction to lowest or simplest terms, divide the numerator and denominator by their (GCF). Note that (GCF) is also called Greatest Common Factor .

So, lets take a sample fraction and reduce into simpler terms.

Considering the fraction

$\frac{45}{100}$

$\mathrm{Find\:a\:common\:factor\:of\:}45\mathrm{\:and\:}100\mathrm{\:in\:order\:to\:cancel\:it\:out}$

$\mathrm{Greatest\:Common\:Divisor\:of\:}45,\:100:\quad 5$

$\mathrm{Factor\:out\:}5\mathrm{\:from\:the\:numerator\:and\:the\:denominator}$

$45=5\cdot \:9\mathrm{,\:\quad }100=5\cdot \:20$

$\frac{45}{100}=\frac{5\cdot \:\:9}{5\cdot \:\:20}$

$\mathrm{Cancel\:the\:common\:factor:}\:5$

$=\frac{9}{20}$

Therefore, the simplest form of the fraction $\frac{45}{100}$ is $\frac{9}{20}$ .

i.e.

$\frac{45}{100}=\frac{9}{20}$

4 0

4 years ago

Help me please <br> bddbdbbdbd

Lostsunrise [7]

35 cats (70%) 15 dogs (30%)

50 x 70% = 35

50 - 35 = 15 (remaining 30%)

1. Find the amount of cats.
2. There are 50 dogs and cats, 30% are dogs.
3. multiplication
4. Formula shown above

Hope this helps!

8 0

3 years ago

Each day a commuter takes a bus to work, the transportation system has a phone app that tells her what time the bus will arrive.

Paraphin [41]

Answer:

Step-by-step explanation:

Hello!

The commuter is interested in testing if the arrival time showed in the phone app is the same, or similar to the arrival time in real life.

For this, she piked 24 random times for 6 weeks and measured the difference between the actual arrival time and the app estimated time.

The established variable has a normal distribution with a standard deviation of σ= 2 min.

From the taken sample an average time difference of X[bar]= 0.77 was obtained.

If the app is correct, the true mean should be around cero, symbolically: μ=0

a. The hypotheses are:

H₀:μ=0

H₁:μ≠0

b. This test is a one-sample test for the population mean. To be able to do it you need the study variable to be at least normal. It is informed in the test that the population is normal, so the variable "difference between actual arrival time and estimated arrival time" has a normal distribution and the population variance is known, so you can conduct the test using the standard normal distribution.

$Z_{H_0}= \frac{X[bar]-Mu}{\frac{Sigma}{\sqrt{n} } }$