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3 years ago

Please help me. I want to get a on this assignment.

Mathematics

2 answers:

Alona [7]3 years ago

5 0

The following that will have no solution is B. It’s B because the final equation is 0 = -5. Which is no solution.

Mamont248 [21]3 years ago

3 0

Answer:

Its B

Step-by-step explanation:

due to 8x cancelling out and leaving 5 to equal to nothing there is no solution.

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Hunter-Best [27]

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2 years ago

Vinnie Testerverte is standing on the 40 yard line of the Washington Redskins when he throws a pass towards his end zone. The

drek231 [11]

Answer:

a.35.25

b. 42.56

c.23.06

Step-by-step explantion

Just subsitute 30, 15, and 5 for x each time for each question

ex:

y=-0.0975(5)^(2)+3.9(5)+6

6 0

3 years ago

Solve the triangle given that a=19 b=16, c=11.

kirill [66]

Answer:

The angles of the triangle are approximately 87.395º, 57.271º and 35.334º.

Step-by-step explanation:

From statement we know all sides of the triangle ( $a$ , $b$ , $c$ ), but all angles are unknown ( $A$ , $B$ , $C$ ). (Please notice that angles with upper case letters represent the angle opposite to the side with the same letter but in lower case) From Geometry it is given that sum of internal angles of triangles equal 180º, we can obtain the missing information by using Law of Cosine twice and this property mentioned above.

If we know that $a = 19$ , $b = 16$ and $c = 11$ , then the missing angles are, respectively:

Angle A

$a^{2} = b^{2}+c^{2}-2\cdot b\cdot c \cdot \cos A$ (1)

$A = \cos^{-1}\left(\frac{b^{2}+c^{2}-a^{2}}{2\cdot b\cdot c} \right)$

$A = \cos^{-1}\left[\frac{16^{2}+11^{2}-19^{2}}{2\cdot (16)\cdot (11)} \right]$

$A \approx 87.395^{\circ}$

Angle B

$b^{2} = a^{2}+c^{2}-2\cdot a\cdot c \cdot \cos B$ (2)

$B = \cos^{-1}\left(\frac{a^{2}+c^{2}-b^{2}}{2\cdot a\cdot c} \right)$

$B = \cos^{-1}\left[\frac{19^{2}+11^{2}-16^{2}}{2\cdot (19)\cdot (11)} \right]$

$B\approx 57.271^{\circ}$

Angle C

$C = 180^{\circ}-A-B$

$C = 180^{\circ}-87.395^{\circ}-57.271^{\circ}$

$C = 35.334^{\circ}$

The angles of the triangle are approximately 87.395º, 57.271º and 35.334º.

8 0

3 years ago

Statistics professors believe the average number of headaches per semester for all students is more than 18. From a random sampl

kompoz [17]

Complete Question

Statistics professors believe the average number of headaches per semester for all students is more than 18. From a random sample of 15 students, the professors find the mean number of headaches is 19 and the standard deviation is 1.7. Assume the population distribution of number of headaches is normal.the correct conclusion at $\alpha =0.001$ is?