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Flura [38]
2 years ago
7

Set up a system of linear equations to represent the scenario. Solve the system by using Gaussian elimination or Gauss-

Mathematics
1 answer:
lapo4ka [179]2 years ago
7 0

She invested $11,250 in the stock, $3,750 in the CD and $12,000 in the bond fund.

<h3><u>Distributions</u></h3>

Given that Sylvia invested a total of $27,000, and she invested part of the money in a certificate of deposit (CD) that earns 3% simple interest per year, she invested in a stock that returns the equivalent of 7% simple interest, and she invested in a bond fund that returns 2%, and she invested three times as much in the stock as she did in the CD, and earned a total of $1140 at the end of 1 yr, to determine how much principal did she put in each investment, the following calculation must be made:

  • 9000 x 0.07 + 3000 x 0.03 + 15000 x 0.02 = 630 + 90 + 300 = 1020
  • 9900 x 0.07 + 3300 x 0.03 + 13800 x 0.02 = 693 + 99 + 276 = 1068
  • 12,000 x 0.07 + 4,000 x 0.03 + 11,000 x 0.02 = 840 + 120 + 220 = 1,180
  • 11400 x 0.07 + 3800 x 0.03 + 11800 x 0.02 = 798 + 114 + 236 = 1148
  • 10800 x 0.07 + 3600 x 0.03 + 12600 x 0.02 = 756 + 108 + 252 = 1116
  • 11160 x 0.07 + 3720 x 0.03 + 12120 x 0.02 = 781.2 + 111.6 + 242.4 = 1135.2
  • 11190 x 0.07 + 3730 x 0.03 + 12080 x 0.02 = 783.3 + 111.9 + 241.6 = 1136.8
  • 11250 x 0.07 + 3750 x 0.03 + 12000 x 0.02 = 787.5 + 112.5 + 240 = 1140

Therefore, she invested $11,250 in the stock, $3,750 in the CD and $12,000 in the bond fund.

Learn more about distribution in brainly.com/question/10250387

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kirill115 [55]

Answer:

There are 12 sets of four marbles include all the red ones.    

Step-by-step explanation:

Given : A bag contains three red marbles, two green ones, one lavender one, four yellows, and five orange marbles.

To find : How many sets of four marbles include all the red ones?

Solution :

Number of red marbles = 3

Number of green marbles = 2

Number of lavender marbles = 1

Number of yellow marbles = 4

Number of orange marbles = 5

We have to form sets of four marbles include all the red ones,

For position of getting red ones we have three red marbles i.e. ^3C_3

For the fourth one we have 12 choices i.e. ^{12}C_1

Total sets of four marbles include all the red ones is

=^3C_3\times ^{12}C_1

=1\times 12

=12

Therefore, There are 12 sets of four marbles include all the red ones.

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3 years ago
Mrs. Bailey gives a test, and her students’ scores range from 30 to 70. She decides to curve the scores, so that they range from
Harman [31]

Answer:

f(x) = x*3/4 + 42.5

Step-by-step explanation:

The original difference between the pair is 70 - 30 = 40

The new difference between the pair is 95 - 65 = 30

Since the differences are not the same, Mrs Bailey must first perform a (slope) multiplication by a factor of 30/40 or 3/4

Then 30 * 3/4 = 22.5

Then she can shift the scores up by 65 - 22.5 = 42.5 in order to get the range from 65 to 95

Therefore, f(x) = x*3/4 + 42.5. We can test that

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Answer:

you answer is <u>7x - 16</u>

4x - 1

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3 years ago
How do you solve f(x) = x2 + x - 20?​
Darina [25.2K]

\huge \bf༆ Answer ༄

Let's solve ~

{ \qquad{ \sf{ \dashrightarrow}}}  \:  \: \sf \: {x}^{2}  + x - 20

{ \qquad{ \sf{ \dashrightarrow}}}  \:  \: \sf \: {x}^{2}  + 5x - 4x - 20

{ \qquad{ \sf{ \dashrightarrow}}}  \:  \: \sf \:x(x + 5) - 4(x + 5)

{ \qquad{ \sf{ \dashrightarrow}}}  \:  \: \sf \:(x + 5)(x -  4)

It's factorized now ~ And if you want to find the zeros then equate the expression with 0.

And you will get ;

{ \qquad{ \sf{ \dashrightarrow}}}  \:  \: \sf \:x =  - 5 \:  \: and \:  \: 4

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