The standard equation of a circle is expressed as
(x - h)^2 + (y - k)^2 = r^2
where
h is the x coordinate of the center of the circle
k is the y coordinate of the center of the circle
r is the radius of the circle(the distance from the center of the circle to the circumference
From the graph,
h = - 1
y = 4
r = 5
By substituting these values into the equation, we have
(x - - 1)^2 + (y - 4)^2 = 5^2
(x + 1)^2 + (y - 4)^2 = 25
Thus, the equation of the circle is
(x + 1)^2 + (y - 4)^2 = 25
The position function of a particle is given by:
The velocity function is the derivative of the position:
The particle will be at rest when the velocity is 0, thus we solve the equation:
The coefficients of this equation are: a = 2, b = -9, c = -18
Solve by using the formula:
Substituting:
We have two possible answers:
We only accept the positive answer because the time cannot be negative.
Now calculate the position for t = 6:
Your fraction answer would be I think 1/15
Ok, so IDK if I'm about to do this problem right, but here we go;
so first, lets change these all to decimals (I more of a decimal gal)
3 1/2 = 3.5
3 2/3 = 3.6666 (repeating)
3 3/5 = 3.6
3 3/8 = 3.375
So now, just order them from greatest to least.
3.66666, 3.6, 3.5, 3.375.
Now, change them back to fractions.
3 2/3, 3 3/5, 3 1/2, 3 3/8
So, if I'm correct, the answer is 3 2/3%, 3 3/5%, 3 1/2%, 3 3/8%
Hopefully I solved your problem!
Greetings!
"<span>What is the general process for solving an equation with one variable?"...
Typically when solving an equation with one variable, your objective is to
isolate the variable on one side of the equation. This can be done adding/subtracting number to cancel them out on one side. You can also multiply/divide coefficients in order to isolate a variable.
Example:</span>
<span>Add
-4 to both sides to isolate the variable.
</span>
<span>
Simplify.
</span>
Divide both sides by
2 to isolate the variable on one side.
Hope this helps.
-Benjamin