I agree with the 14x all right, but the remainder of the other part is 178. I'm going to recheck my answer. I'm not confident about using synthetic division for this question. It is 57 years since I did something like this. If I was more confident, I would list the results of synthetic division because it is much easier to show than long division. I'm saying the answer should be 14x + 178.
I think it’s 1/5 simplified
Answer:
The 98% confidence interval estimate of the proportion of adults who use social media is (0.56, 0.6034).
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of
, and a confidence level of
, we have the following confidence interval of proportions.

In which
z is the zscore that has a pvalue of
.
Of the 2809 people who responded to survey, 1634 stated that they currently use social media.
This means that 
98% confidence level
So
, z is the value of Z that has a pvalue of
, so
.
The lower limit of this interval is:

The upper limit of this interval is:

The 98% confidence interval estimate of the proportion of adults who use social media is (0.56, 0.6034).
Answer:
24 to 34? = 41.67%.
Step-by-step explanation: