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2 years ago

50 POINTS PLS HELP

Mathematics

2 answers:

Andreas93 [3]2 years ago

6 0

${}$

ANSWER:

SOLUTION:

1) The y-intercept is the value of the function, for x = 0.

2) So, to find the y-intercept when you have the function, you need to solve the equation for y when x = 0.

For example if the function is y = f(x) = x^2 + 5, the y-intercept is y = f(0) = 0^2 + 5 = 5. 3) Graphically, the y-intercept is the point

where the graph of f(x) crosses the y-axis.

So, if you have the graph, you just read the value of the function on the y-axis.

Taking all that information, you do not report the y-intercept as a pair of coordinates. The y-intercept is reported just as a value for y.

For example, assuming that the point (0, - 4) you do not say that the y-intecept is (0,-4), you say that the y-intecept is -4, because that is the value of the function when x = 0.

egoroff_w [7]2 years ago

4 0

Answer:

Step-by-step explanation:

find value at 12 =12

find value at 10 = 6

so it changes + 6 for a change from 10 to 12

6/2 = 3

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Elena L [17]

N + (3n - 15) = 101 is the equation, the answer to the equation is 29

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3 years ago

What are the potential solutions to the equation 2ln(x+3)=0

skad [1K]

$2\ln(x+3)=0\implies \ln(x+3)^2=0\implies e^{\ln(x+3)^2}=e^0\implies (x+3)^2=1$

Expanding the left side gives

$x^2+6x+9=1\implies x^2+6x+8=0\implies (x+4)(x+2)=0$

which gives two solutions, $x=-4$ and $x=-2$ . But if $x=-4$ , then $\ln(x+3)=\ln(-1)$ , but this number isn't real, so $x=-4$ is an extraneous solution. Meanwhile if $x=-2$ , you get $\ln(-2+3)=\ln1=0$ , so this solution is correct.

"Potential solutions" might refer to both possibilities, but there is only one actual (real) solution.

4 0

3 years ago

Read 2 more answers

Ted Thomason found a good deal when he purchased a bedding set. He paid the store's clerk two $20 bills and a $5 bill. The clerk

Lina20 [59]

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3 years ago

Find the average rate of change of k(x)=5x–19 over the interval [<br> -<br> 14,<br> -<br> 4].

rusak2 [61]

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$\frac{\Delta{k{x)}}{\Delta{x}}$

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$\Delta{x}=-4-(-14)=10$

To find the change in k(x), we can calculate the values of k(x) at x = -14 and x = -4 and find the difference between them:

$k(-14)=5(-14)-19=-70-19=-89\\ k(-4)=5(-4)-19=-20-19=-39\\ \Delta{y}=k(-14)-k(-4)=-89-(-39)=-50$

So, the rate of change for the function from x = -14 to x = -4 is

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3 years ago

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babunello [35]

Answer:

the answer is true

Step-by-step explanation:

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3 years ago