It can browse the document by headings.
Answer:
1. Scanner = reading passports.
2. Barcode reader = automatic stock control.
3. pH sensor = monitor soil in a greenhouse.
4. Microphone = voice recognition.
Explanation:
1. Scanner: Copies paper documents and converts the text and pictures into a computer-readable form. Therefore, it can be used for reading passports.
2. Barcode reader: reads labels containing parallel dark and light lines using laser light or LEDs; the width of each line represents a binary code. Therefore, it is used for automatic stock control.
3. pH sensor: detect changes in acidity levels; data is often in analogue form. Thus, it is typically used to monitor soil in a greenhouse.
4. Microphone: allows audio signals to be converted into electric signals; these can be interpreted by a computer after being converted into digital form. Microphones are used for voice recognition.
Answer:
A. True.
Explanation:
E-mail is an acronym for electronic mail and it can be defined as an exchange or transmission of computer-based data (messages) from one user to another over a communications network system.
Also, a distributed application refers to a software program that is capable of running on several computer systems and can communicate effectively through a network.
E-mail is the most common distributed application that is widely used across all architectures and vendor platforms because it primarily operates on a client-server model, by providing users with the requested services through the Simple Mail Transfer Protocol (SMTP) using the standard port number of 25.
Answer:
What are you trying to say?
Explanation:
Answer:
(s.charAt(0) != s.charAt(s.length()-1))
Explanation:
public class Palindrome
{
public static void main(String[] args) {
System.out.println(isPalindrome("car"));
System.out.println(isPalindrome("carac"));
}
public static boolean isPalindrome(String s) {
if (s.length() <= 1)
return true;
else if (s.charAt(0) != s.charAt(s.length()-1))
return false;
else
return isPalindrome(s.substring(1, s.length() - 1));
}
}
You may see the whole code above with two test scenarios.
The part that needs to be filled is the base case that if the character at position 0 is not equal to the character at the last position in the string, that means the string is not a palindrome. (If this condition meets, it checks for the second and the one before the last position, and keeps checking)
