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galben [10]
2 years ago
6

What is the area of a regular hexagon with a side length of 4 m? enter your answer in the box. round only your final answer to t

he nearest hundredth. m²
Mathematics
1 answer:
N76 [4]2 years ago
5 0

Answer:

41.57

Step-by-step explanation:

took the test

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A. What is the vertex of the equation y = (x - 4)??
Contact [7]

Good morning,

Answer:

(4 , 0)

Step-by-step explanation:

THe vertex of y = (x - 4)² is (4,0).

Look at the photo below for the graph.

:)

8 0
3 years ago
Someone please help me
Irina18 [472]

Answer:

a) Angle XBC = 55° because it's a corresponding angle

AXY = XBC

b) 180° - (55° × 2) = 70°

7 0
3 years ago
Please help due ASAP <br> Show workings please
Nostrana [21]

Step-by-step explanation:

I don't know if this is the right way to so it, but I would do it like this

since a triangle has 180 degrees, the angles all have to add up to 180

So 180 = a + b + c

we already know a, its 95

So 180 = 95 + b + c

now we know the equation for b, so we'll just put it there instead of the b, and since the angles are the same, we should put it instead of c too

180 = 95 + (4x-15) + (4x-15)

now subtract 95 from both sides

85 = (4x-15) + (4x-15)

add the xs and numbers together

85 = 8x - 30

now add the 30 to both sides

115 = 8x

divide by 8

your x is 14 3/8 or 14.375 or 115/8

that's not your angle, that's your x

5 0
3 years ago
The county hospital is located at the center of a square whose sides are 3 miles wide. If an accident occurs within this square,
Dmitry_Shevchenko [17]

Answer:

3

Step-by-step explanation:

The x-coordinate of the accident is a random variable of uniform distribution with range [-1.5,1.5]. The same can be said for the y-coordinate. However, |x| and |y| are also uniform variables with range [0,1.5], since we still have the same probability on every pair of intervals with the same lenght.

Note that |X| and |Y| are independent with each other, therefore E(|x|+|y|) = E(|x|) + E(|y|) = 2*E(|x|). The last equality holds because both x and y are identically distributed, then so are |x| and |y|.

E(|x|) = \int\limits^{1.5}_0 {\frac{x}{1.5} \, dx = \frac{2}{3}* ((1.5^2)/2 - 0^2/2) = \frac{3}{2}

Therefore, E(|x| + |y|) = 2 * 3/2 = 3.

I hope that works for you!

4 0
3 years ago
50 POINTS!!!! NEED ANSWER FAST!!!<br><br> SEE PICTURES BELOW!
Semenov [28]

1. given

2.RPoC

4.   qxa qya

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3 years ago
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