We try to represent each number inside the square root as a product of a square and another number.
a) 7√32 - 5√2 + √8
√32 = √(16 *2) = √16 * √2 = 4* √2 = 4√2
√8 = √(4 *2) = √4 * √2 = 2* √2 = 2√2
7√32 - 5√2 + √8 = 7*(4√2) - 5√2 + 2√2 =
= 28√2 - 5√2 + 2√2 Factorize out √2
= (28 - 5 + 2)√2
= 25√2
b) 2√150 - 4√54 + 6√24
√150 = √(25 * 6) = √25 * √6 = 5*√6 = 5√6
√54 = √(9 * 6) = √9 * √6 = 3*√6 = 3√6
√24 = √(4 * 6) = √4 * √6 = 2*√6 = 2√6
2√150 - 4√54 + 6√24 = 2*(5√6) - 4*(3√6) + 6*(2√6)
= 2*5√6 - 4*3√6 + 6*2√6
= 10√6 - 12√6 + 12√6 Factorize √6
= (10 - 12 + 12)√6
= 10√6
The correct answer is that Hector placed Puppy 3 at -3.4 instead of at -0.75.
So A would be your correct answer. -3/4 is equivalent to -0.75. Think of it like money. 4 quarters equals $1.00. 3 quarters is 75 cents, or .75 which is this. Don’t forget the signs though. God bless you.
The price of a senior citizen ticket is $8 and the price of a student ticket is$ 10
Step-by-step explanation:
Let the cost of one seniors citizen ticket be x and student be y
First day:
10 seniors citizen tickets and 11 student for a total of $190.
10x + 11y = 190-----------------------------(1)
Second day:
$160 on the second day by selling 5 senior citizen tickets and 12 student tickets.
5x + 12y = 160---------------------------------(2)
Multiply eq(2) by 2
10x + 24y = 320----------------------------(3)
Subtract eq(1) from (3)
10x + 24y = 320
10x + 11y = 190
-----------------------------
0x + 13 y = 130
---------------------------
13y = 130
y = 10-------------------------------(4)
Substituting (4) in (2)
5x + 12(10) = 160
5x + 120 = 160
5x = 160-120
5x = 40
x = 8
Answer:
x= -18
Step-by-step explanation:
We want to isolate x ( move everything to the other side of the equation)
-7 = -1 + x/3
-6 = x/3
x= 3*-6
x= -18
Answer:
K 20
Step-by-step explanation:
f(x) = 7x2 - 4x
f (2) = 7 (2)^2 - 4(2)
= 28 - 8
= 20
Since they replaced the x inside f(x) with 2, just do that the same to the right side, change all x into 2
