3(2x+14)divided by w-y if w=8,x=5,y=1 how do i solve this

1 answer:

3 0

$\frac{3 (2x + 14)}{w - y}$
$w = 8, x = 5, y = 1$

You have to first substitute every variable into its spot in the equation.

 $\frac{3 (2x + 14)}{w-y}$
 $\frac{3 (2*5 + 14)}{8 - 1}$

Then solve.

$\frac{3 (28)}{7} = \frac{84}{7} = 12$

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A roulette wheel has the numbers 1 through 36, 0, and 00. A bet on three numbers pays 11 to 1 (that is, if you bet $1 and one of

OLga [1]

Answer:

You are expected to lose $0.05 (or win -$0.05)

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$P(W)=\frac{3}{38}\\P(L) = 1 - P(W)\\P(L) = \frac{35}{38}\\$

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$EV = (11*\frac{3}{38}) -(1*\frac{35}{38})\\EV = -\$0.0525$