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Anastaziya [24]
2 years ago
5

9. Jules wrote the expression below, but the

Mathematics
1 answer:
Leona [35]2 years ago
5 0

Both expressions illustrate the use of algebraic expressions.

The missing term of -46x + 18 is 2

The expressions are given as:

-4(12x - 5) + 2x and -46x + 18

Let the first term of -46x + 18 be represented with variable y.

So, we have:

y -46x + 18

Equate both expressions

-4(12x - 5) + 2x = y -46x + 18

Open brackets

-48x + 20 + 2x = y -46x + 18

Collect like terms

y = 46x - 48x + 2x + 20 - 18

y = 0 + 2

y = 2

Hence, the missing term is 2

Read more about algebraic expressions at:

brainly.com/question/11227332

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Jack is playing a game. When a player wins 3 consecutive games, the player receives 10 bonus points and then the player’s total
svlad2 [7]
Let Jack's current point is p

After winning 3 consecutive games, the bonus point is given by
b(p)=p+10

The score after 5% = 0.05 increase is
s(p)= (1+0.05)p=1.05p

(s.b)(p)=1.05(p+10)=1.05p+10.5


3 0
4 years ago
Which table represents a linear function
AlexFokin [52]

Answer:

3rd option (top right)

Step-by-step explanation:

3rd option represents a linear equation

y = -2x-1

Answered by GAUTHMATH

6 0
3 years ago
3-(12-6÷3)+7(3×2-5)​
insens350 [35]

Answer:

Solutions

Step-by-step explanation:

3-(12-2)+7(3*2-5)

3-10+7(6-5)

3-10+7*1

3-17

-14

8 0
3 years ago
Read 2 more answers
Find the missing length indicated​
Rina8888 [55]

Answer:

c = 175

Step-by-step explanation:

When the height of a right triangle is shown this way (at right angles with the hypotenuse, It can be found by using the way the hypotenuse is broken up. The following proportion works.

576/x = x / 49          Cross multiply

x^2 = 576 * 49

sqrt(x^2) = sqrt(576*49)

x = 24 * 7

x = 168

But that's not what you want (although it is close).

What you want is the hypotenuse to the small lower triangle

c = ?

a = 49

b = 168

c^2 =  49^2 + 168^2

c^2 = 2401 + 28224

c^2 = 30625

c = sqrt(30625)

c = 175

4 0
3 years ago
-6c+x find the expression
Romashka [77]

Answer:

https://www.khanacademy.org/math/algebra/introduction-to-algebra/alg1-writing-expressions/v/writing-expressions-1

Step-by-step explanation:


7 0
3 years ago
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