To factor quadratic equations of the form ax^2+bx+c=y, you must find two values, j and k, which satisfy two conditions.
jk=ac and j+k=b
The you replace the single linear term bx with jx and kx. Finally then you factor the first pair of terms and the second pair of terms. In this problem...
2k^2-5k-18=0
2k^2+4k-9k-18=0
2k(k+2)-9(k+2)=0
(2k-9)(k+2)=0
so k=-2 and 9/2
k=(-2, 4.5)
Answer:
$883.40
Step-by-step explanation:
Calculate the amount of money needed to pay after the discount.n
$1049 × 88% = $923.12
Calculate the amount of money needed to pay after the tax.
$923.12 × 104.5% = $883.3684210526
=$883.40(rounded off to nearest cents)
hope this helps
Divide fractions by multiplying the first number by the reciprocal of the second.
2ay*15y= 30ay^2
5y^3*4a=20ay^3
(30ay^2)/(20ay^3)=3/(2y)
Final answer: 3/(2y)
Answer:
(0, -5)
Step-by-step explanation:
The function 
is incresing and have positive values for all x. Then the function 
is also increasing and have positive values for all x. This means that options B (values are negative) and D (function is decreasing) are incorrect.
At x=0, 
.
In option A graph of the function passes through point (0,y), where y is near 3. In option C graph of the function passes through point (0,y), where y is near 1/5. So, you can conclude that the option C is correct.
