A two-digit number is twice the sum of its digit. If the tens digit is 7 less than the unit digit, find the number.
Let x= the unit digit
Then y= the tens digit
<span>And 10y+x= the number
</span>x+y= the sum of the digits
<span>Now we are told that 10y+x=2(x+y) ------1st equation </span>
<span>We are also told that y=x-7 ----------- 2nd Equation </span>
<span>So our equations to solve are: </span>
(1) 10y+x=2(x+y)
<span>(2) y=x-7
</span>
Hope it helps
Answer:
0
Step-by-step explanation:
Given that,
6m - 2n=0
=>6m=2n
=>n=3m [divide both side by 2]
& mn=12
Now,
216c - 8n³
= 216m³- 8(3m)³
=216m³- 8 .27m³
=216m³- 216m³
=0
Differentiate both sides with respect to <em>x</em>, assuming <em>y</em> = <em>y</em>(<em>x</em>).
Solve for d<em>y</em>/d<em>x</em> :
If <em>y</em> ≠ 0, we can write
At the point (1, 1), the derivative is
