PLS HELP

Ivan rented a truck for one day. There was a base fee of $18.99 , and there was an additional charge of 91 cents for each mile d

Sloan [31]

Answer:

146 miles

Step-by-step explanation:

hope this is correct

7 0

2 years ago

Read 2 more answers

R/3+2=21 solve for r

olchik [2.2K]

Answer:

r=63

Step-by-step explanation:

Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation :

r/3-(21)=0 r

Simplify —

3

r

— - 21 = 0

3 2.1 Subtracting a whole from a fraction

Rewrite the whole as a fraction using 3 as the denominator :

21 21 • 3

21 = —— = ——————

1 3

Equivalent fraction : The fraction thus generated looks different but has the same value as the whole

Common denominator : The equivalent fraction and the other fraction involved in the calculation share the same denominator

7 0

3 years ago

Captain Salamander has a lazy time on the trip and spends about 15 hours a day sleeping. What fraction of the day does he spend

padilas [110]

Well there is 24 hours in a day so 24 - 15 = 9. So he spends 9 hours awake.

7 0

3 years ago

An automobile manufacturer would like to know what proportion of its customers are not satisfied with the service provided by th

monitta

Answer:

a) n =1623

b) $ME=2.0538\sqrt{\frac{0.21 (1-0.21)}{1623}}=0.0208$

Step-by-step explanation:

1) Notation and definitions

$n$ random sample taken

$\hat p=0.19$ estimated proportion of customers are not satisfied with the service provided by the local dealer

Confidence =0.96 or 96%

Me= 0.02 represent the margin of error

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The population proportion have the following distribution

$p \sim N(p,\sqrt{\frac{p(1-p)}{n}})$

Part a

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 96% of confidence, our significance level would be given by $\alpha=1-0.96=0.04$ and $\alpha/2 =0.02$ . And the critical value would be given by: