Unfortunately there isn't enough information.
Check out the diagram below. We have segment BC equal to 120 meters long. Points B, C, D and E are all on the edge of the same circle. According to the inscribed angle theorem, angles BDC and BEC are congruent. This shows that the surveyor could be at points D or E, or the surveyor could be anywhere on the circle. There are infinitely many locations for the surveyor to be at, which leads to infinitely many possible widths of this canal.
If you mean (3n-2m)^2 then the answer is
9n^2-12mn+4m^2
So B
Answer:
80 square meters
Step-by-step explanation:
A rectangle that is partitioned into two rectangles; rectangle A and rectangle B
Rectangle A:
Top = 5 meters
Side = 8 meters
Area of rectangle A = length × width
= 5 meters × 8 meters
= 40 meters ²
Rectangle B:
Top = 5 meters
Side = 8 meters
Area of rectangle B = length × width
= 5 meters × 8 meters
= 40 meters ²
Total area of the partitioned rectangle = area of rectangle A + area of rectangle B
= 40 meters ² + 40 meters ²
= 80 meters ²
Answer:
14
Step-by-step explanation:
-21+-13+20=14
This is true because when subtracting negatives by negatives you pretty much add them and then when you add a positive to a negative you are technically removing the negative by the amount you are adding.
In short its kind of like using inverse operation in a way.
Hope this helps and have a nice day
Also may I please have a brainliest!!!
Answer:
1. Answer is 162 2. Answer is 159.2
Step-by-step explanation:
In the first one we calculate both triangles by using and multiply it by 2 since we have 2 triangles
then we calculate the rectangle
and then we put them all together and get the answer which is 162.
in the second one we calculate the trapezoid then rhombus, then we put them together and get our answer which is 159.2
