Well if she is making dinner for 10 people and each person want 2 pieces then you need to multiple 10 x 2 = 20. So she is going to need to make 20 pieces.
If each of her pumpkin pies only has 8 pieces then she is going to have to make 3 pies.
3 pies x 8 pieces = 24 pieces of pumpkin pie. So she has to make 3 pies because she needs 20 pieces since everyone wants 2.
In conclusion Mrs. Owens has to make 3 pies and she is going to have 4 pieces left over.
(p+1) (p-1). solved this on paper . hope it helps .
A. You may set the variables in either order. But for argument sake, let's set as follows:
x = Amount of bookshelves
y = Amount of tables
B. Because of the amount of things you need to make, the following is an inequality using those variables.
x + y > 25
Plus you can determine a second inequality based on the amount of money that you have to spend.
20x + 45y < 675
Finally you may also add in that each value must be greater than or equal to zero, since they cannot have negative tables.
C. By solving the system and looking at basic constraints when graphed, you can see the feasible region has 4 vertices.
(0,0)
(18, 7)
(0, 15)
(33.75, 0) or (33, 0) if you insist on rounding.
1) 2m+6 / m² + 7m - 12 + (m+2)/(m+4)
= 2(m+3) / (m+4)(m+3) + (m+2)/(m+4)
= 2/(m+4) + (m+2)/(m+4)
= 2+m+2 / (m+4)
= m+4 / m+4
= 1 [ Option A ]
Answer 2) 3/ (x+4) + 7/ (x-3)
= 3(x-3) + 7(x+4)/ (x² +x - 12)
= 3x-9 + 7x + 28 / (x² +x - 12)
= 10x + 19 / (x² +x - 12) [ Option A ]
Hope this helps!
