Question

Line JK passes through points J(-4,-5) and K(-6,3). If the equation of the line is written in slope-intercept form, y-mx+b, what is the value of b?

Answer 1

$m = \frac{y_{2} - y_{1}}{x_{2} - x_{1}} = \frac{3 - (-5)}{-6 - (-4)} = \frac{3 + 5}{-6 + 4} = \frac{8}{-2} = -4$

   y - y₁ = m(x - x₁)
y - (-5) = -4(x - (-4))
   y + 5 = -4(x + 4)
   y + 5 = -4(x) - 4(4)
   y + 5 = -4x - 16
       - 5           - 5
         y = -4x - 21

Answer 2

the answer is -21 for the people who don't want to read all that