Line JK passes through points J(-4,-5) and K(-6,3). If the equation of the line is written in slope-intercept form, y-mx+b, what
is the value of b?
2 answers:
![m = \frac{y_{2} - y_{1}}{x_{2} - x_{1}} = \frac{3 - (-5)}{-6 - (-4)} = \frac{3 + 5}{-6 + 4} = \frac{8}{-2} = -4](https://tex.z-dn.net/?f=m%20%3D%20%5Cfrac%7By_%7B2%7D%20-%20y_%7B1%7D%7D%7Bx_%7B2%7D%20-%20x_%7B1%7D%7D%20%3D%20%5Cfrac%7B3%20-%20%28-5%29%7D%7B-6%20-%20%28-4%29%7D%20%3D%20%5Cfrac%7B3%20%2B%205%7D%7B-6%20%2B%204%7D%20%3D%20%5Cfrac%7B8%7D%7B-2%7D%20%3D%20-4)
y - y₁ = m(x - x₁)
y - (-5) = -4(x - (-4))
y + 5 = -4(x + 4)
y + 5 = -4(x) - 4(4)
y + 5 = -4x - 16
- 5 - 5
y = -4x - 21
the answer is -21 for the people who don't want to read all that
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