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mylen [45]
3 years ago
11

Suppose f(x) = x^3. Find the graph of f(x+5)

Mathematics
1 answer:
Sophie [7]3 years ago
7 0

Step-by-step explanation:

work work work :)

Love you

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Find the total surface area and volume, then multiply by 0.0004
Maksim231197 [3]

The Total surface area of the rectangular prism = 168 in.²

The Volume of the rectangular prism = 108 in.³

<h3>What is the Total Surface Area of a Rectangular Prism?</h3>

The total surface area of a rectangular prism is given as: SA = 2(wl + hl + hw), where:

w = width of the rectangular prism

h = height of the rectangular prism

l = length of the rectangular prism

<h3>What is the Volume of a Rectangular Prism?</h3>

The volume of a rectangular prism = l × w × h

Find the Total surface area of the rectangular prism:

Length (l) = 9 in.

Width (w) = 2 in.

Height (h) = 6 in.

Total surface area of the rectangular prism = 2(wl+hl+hw) = 2·(2·9+6·9+6·2) = 168 in.²

Find the volume of the rectangular prism:

Length (l) = 9 in.

Width (w) = 2 in.

Height (h) = 6 in.

Volume of the rectangular prism = l × w × h = 9 × 2 × 6

Volume of the rectangular prism = 108 in.³

Learn more about the rectangular prism on:

brainly.com/question/1015291

#SPJ1

7 0
1 year ago
Graph the function y = 8 –. Which is the best approximation of a point on the function? (4.4, 3.421) (4.6, 4.232) (5.2, 4.025) (
Trava [24]

Answer: (5.9, 3.781)

6 0
3 years ago
5) Jim is hoping that a park will be built
Sedaia [141]

Answer:

Step-by-step explanation:

7 0
2 years ago
Write a unit rate for the situation. $1.98 for 6 bananas
USPshnik [31]
A unit rate is when you find a rate when one variable (or value) is equal to one.

Let's find the unit rate for the price of the bananas. 

1.98/6= 0.33

It is 33 cents for one banana. That is the unit rate. 

I hope this helps!
~kaikers
4 0
2 years ago
An object is launched from a launching pad 144 ft. above the ground at a velocity of 128ft/sec. what is the maximum height reach
ollegr [7]

Answer:

18) a. h(x) = -16x² + vx + h(0) ⇒ h(x) = -16x² + 128x + 144

b. The maximum height = 400 feet

c. Attached graph

19) The rocket will reach the maximum height after 4 seconds

20) The rocket hits the ground after 9 seconds

Step-by-step explanation:

* Lets study the rule of motion for an object with constant acceleration

# The distance S = ut ± 1/2 at², where u is the initial velocity, t is the time

  and a is the acceleration of gravity

# The vertical distances h in x second is h(x) - h(0), where h(0)

   is the initial height of the object above the ground

∵ h(x) = vx + 1/2 ax², where h is the vrtical distance, v is the initial

  velocity, a is the acceleration of gravity (32 feet/second²) and x

  is the time

18)a.

∵ The value of a = -32 ft/sec² ⇒ negative because the direction

   of the motion

  is upward

∴ h(x) - h(0) = vx - (1/2)(32)(x²) ⇒ (1/2)(32) = 16

∴ h(x) = vx - 16x² + h(0)

∴ h(x) = -16x² + vx + h(0) ⇒ proved

* Find the height of the object after x seconds from the ground

∵ h(0) = 144 and v = 128 ft/sec

∴ h(x) = -16x² + 128x + 144

b.

* At the maximum height h'(x) = 0

∵ h'(x) = -32x + 128

∴ -32x + 128 = 0 ⇒ subtract 128 from both sides

∴ -32x = -128 ⇒ ÷ -32

∴ x = 4 seconds

- The time for the maximum height = 4 seconds

- Substitute this value of x in the equation of h(x)

∴ The maximum height = -16(4)² + 128(4) + 144 = 400 feet

c. Attached graph

19)

- The object will reach the maximum height after 4 seconds

20)

- When the rocket hits the ground h(x) = 0

∵ h(x) = -16x² + 128x + 144

∴ 0 = -16x² + 128x + 144 ⇒ divide the two sides by -16

∴ x² - 8x - 9 = 0 ⇒ use the factorization to find the value of x

∵ x² - 8x - 9 = 0

∴ (x - 9)( x + 1) = 0

∴ x - 9 = 0 OR x + 1 = 0

∴ x = 9 OR x = -1

- We will rejected -1 because there is no -ve value for the time

* The time for the object to hit the ground is 9 seconds

8 0
2 years ago
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