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USPshnik [31]
2 years ago
15

The width of a golden rectangle is 15 feet. Find the perimeter of the rectangle to the nearest foot.

Mathematics
1 answer:
topjm [15]2 years ago
3 0

Answer:

79 ft

Step-by-step explanation:

Golden rectangle side ratios   1 : (1+sqrt5 )/2

      (approx  1: 1.618)

15 + 15   +  2*15*1.618 = <u>~79 ft </u>

BUT perhaps the 15 is the 1.618 side

15/1.618 + 15/1.618   + 15 + 15   ~ 49 feet

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12in = 12in × (1ft/12in) = 1ft
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3 years ago
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borishaifa [10]

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c^2= a^2+ b^2

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c^2= 1600

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5 0
2 years ago
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vovangra [49]
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3 years ago
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viktelen [127]

19. Perimeter of rectangle = 2(l + b)

l = 25m

b = 16m

Perimeter of rectangular park = 2 (25 + 16)

= 50 + 32

= 82m

Perimeter of square park = 82m

(given that, perimeter of rectangular and square park are equal)

Perimeter of square = 4a

4a = 82

a = 82/4

a = 20.5m

Area of square park = a²

= 20.5²

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20. Perimeter of regular hexagon = 6a

a = 2.5

6a = 6 × 2.5

= 15cm

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a = 8

10a = 10 × 8

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3 years ago
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Whats up? What do you need help with
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3 years ago
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