The length of a rectangle is four times it width. If the perimeter of the rectangle is 70 ft, find its length and width

A new shopping mall is considering setting up an information desk manned by one employee. Based upon information obtained from s

quester [9]

Answer:

a) $P=1-\frac{\lambda}{\mu}=1-\frac{20}{30}=0.33$ and that represent the 33%

b) $p_x =\frac{\lambda}{\mu}=\frac{20}{30}=0.66$

c) $L_s =\frac{20}{30-20}=\frac{20}{10}=2 people$

d) $L_q =\frac{20^2}{30(30-20)}=1.333 people$

e) $W_s =\frac{1}{\lambda -\mu}=\frac{1}{30-20}=0.1hours$

f) $W_q =\frac{\lambda}{\mu(\mu -\lambda)}=\frac{20}{30(30-20)}=0.0667 hours$

Step-by-step explanation:

Notation

P represent the probability that the employee is idle

$p_x$ represent the probability that the employee is busy

$L_s$ represent the average number of people receiving and waiting to receive some information

$L_q$ represent the average number of people waiting in line to get some information

$W_s$ represent the average time a person seeking information spends in the system

$W_q$ represent the expected time a person spends just waiting in line to have a question answered

This an special case of Single channel model

Single Channel Queuing Model. "That division of service channels happen in regards to number of servers that are present at each of the queues that are formed. Poisson distribution determines the number of arrivals on a per unit time basis, where mean arrival rate is denoted by λ".

Part a

Find the probability that the employee is idle

The probability on this case is given by:

In order to find the mean we can do this:

$\mu = \frac{1question}{2minutes}\frac{60minutes}{1hr}=\frac{30 question}{hr}$

And in order to find the probability we can do this:

$P=1-\frac{\lambda}{\mu}=1-\frac{20}{30}=0.33$ and that represent the 33%

Part b

Find the proportion of the time that the employee is busy

This proportion is given by:

$p_x =\frac{\lambda}{\mu}=\frac{20}{30}=0.66$

Part c

Find the average number of people receiving and waiting to receive some information

In order to find this average we can use this formula:

$L_s= \frac{\lambda}{\lambda -\mu}$

And replacing we got:

$L_s =\frac{20}{30-20}=\frac{20}{10}=2 people$

Part d

Find the average number of people waiting in line to get some information.

For the number of people wiating we can us ethe following formula"

$L_q =\frac{\lambda^2}{\mu(\mu-\lambda)}$

And replacing we got this:

$L_q =\frac{20^2}{30(30-20)}=1.333 people$

Part e

Find the average time a person seeking information spends in the system

For this average we can use the following formula:

$W_s =\frac{1}{\lambda -\mu}=\frac{1}{30-20}=0.1hours$

Part f

Find the expected time a person spends just waiting in line to have a question answered (time in the queue).

For this case the waiting time to answer a question we can use this formula:

$W_q =\frac{\lambda}{\mu(\mu -\lambda)}=\frac{20}{30(30-20)}=0.0667 hours$

6 0

3 years ago

Read 2 more answers

I NEED HELL PLZ I don’t get it i need to turn it soon.

Blababa [14]

60% of the class is blonde

7 0

2 years ago

Read 2 more answers

Help pls will give brainliest to correct answer

Marysya12 [62]

D is correct answers

7 0

3 years ago

Please help me i been stuck all day on this. Find the value of x.

erastova [34]

Answer:

14

Step-by-step explanation:

105 and (6x-21) the same. So you do 105 minus 21, then divide that by 6.

7 0

3 years ago

Read 2 more answers

A fuel tank contains 1 3/4 gallons of gasoline. Casey adds 33 1/3 gallons of

romanna [79]

Answer:

The gallons of gas the tank contain now is <u>35 1/12</u>.

Step-by-step explanation:

Given:

Fuel tank contains 1 3/4 gallons of gasoline.

Casey adds 33 1/3 gallons of gasoline to the tank.

Now, to find the total gallons of gas the tank contain.

Converting the mixed fractions into improper.

Gallons of gasoline in fuel tank $=1\frac{3}{4}=\frac{7}{4}$ .

Gallons of gasoline Casey adds $=33\frac{1}{3} =\frac{100}{3}$ .

<u>According to question:</u>

By adding we get the total gallons of gasoline now tank contain:

$\frac{7}{4} +\frac{100}{3}$

$=\frac{7\times 3+100\times 4}{12}$

$=\frac{21+400}{12}$

$=\frac{421}{12}$

$=35\frac{1}{12}$

Therefore, the gallons of gas the tank contain now is 35 1/12.

5 0

3 years ago