Determining a car's depreciation over a ten year period is considered a bivariate.
<h3>What is a bivariate?</h3>
A Bivariate data is made up of two variables that are observed against each other. In determining the deprecation of a car, the cost of the car is observed against the passage of time and the depreciation factor.
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Using it's concept, the range of the function is given as follows:
0 ≤ m ≤ 1200.
<h3>What is the range of a function?</h3>
The range of a function is the set that contains all possible output values for the function.
For this problem, we have to consider these two bullet points next, considering the mass is the output value of the function.
- The smallest possible mass for the substance is of 0 grams, as after the substance decays to 0 grams, it will not assume a negative value, it will just disappear.
- The greatest possible mass for the substance is the initial mass of 1200 grams, as the substance does not adquire mass with time, it just loses it.
Considering these masses, the range of the function is given as follows:
0 ≤ m ≤ 1200.
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I believe the answer is 1.343 x 10^5
Answer:
60
Step-by-step explanation:
