Answer:
Grades 6 and 8
Step-by-step explanation:
If the relationship of girls to boys in two different grades are proportional, <u>they must have the same ratio</u>. To tackle this problem, we can find the <u>ratios</u> of genders in each grade and compare them.
Step 1, finding ratios:
Finding ratios is just like <u>simplifying fractions</u>. We will reduce the numbers by their<u> greatest common factors</u>.
<u>Can't be simplified!</u>
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Step 2:
Notice how grades 6 and 8 both had a ratio of 3:4. We can conclude that these two grades have a proportional relationship between girls and boys.
<em>I hope this helps! Let me know if you have any questions :)</em>
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Answer:
I think see what circuit is connected to the light
Step-by-step explanation:
The length of the sides of any right triangle are always less than the length of the hypotenuse. The sine and cosine functions find the ratio between a side and the hypotenuse, so it's always less than 1.
<span>(x + 5 1/2) 0.75= 5/8<span>
Convert 0.75 into a fraction
</span></span><span>(x + 5 1/2) 3/4= 5/8
Use distributive property
3/4x + 5 1/2*3/4 = 5/8
Convert 5 1/2 into improper fraction
3/4x + 11/2*3/4 = 5/8
Multiply
3/4x + 33/8 = 5/8
Subtract 33/8 from both sides
3/4x = 5/8 - 33/8
Subtract the numerators but NOT the denominators
3/4x = -28/8
Divide 3/4 on both sides
x = -28/8 divided by 3/4
Convert the division sign to multiplication while flipping the fraction 3/4 to 4/3
x = -28/8 * 4/3
Multiply
Final Answer: x = -112/24 or -4 16/24 or -4 4/6 or -4 2/3 *All answers are equivalent to each other.</span>
C doesn’t have a value , x equals 0 , x=0
