The true statement is Line MK is the perpendicular bisector of LN and ML is ≅ MN.
<h3>What is perpendicular?</h3>
Perpendicular lines are lines that intersect at a right (90 degrees) angle.
Given:
Δ LMN and Δ LKN are connected at side LN.
As per the information,
Line MK is the perpendicular bisector of LN. and ML ≅ MN.
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Answer:
42+18=6(7+3)
Step-by-step explanation:
6x7=42 and 6x3=18
Using the normal distribution, it is found that there are 68 students with scores between 72 and 82.
<h3>Normal Probability Distribution</h3>
The z-score of a measure X of a normally distributed variable with mean and standard deviation is given by:
- The z-score measures how many standard deviations the measure is above or below the mean.
- Looking at the z-score table, the p-value associated with this z-score is found, which is the percentile of X.
In this problem, the mean and the standard deviation are given, respectively, by:
The proportion of students with scores between 72 and 82 is the <u>p-value of Z when X = 82 subtracted by the p-value of Z when X = 72</u>.
X = 82:
Z = 1
Z = 1 has a p-value of 0.84.
X = 72:
Z = 0
Z = 0 has a p-value of 0.5.
0.84 - 0.5 = 0.34.
Out of 200 students, the number is given by:
0.34 x 200 = 68 students with scores between 72 and 82.
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You would have to divide 16.50 into 3 then put your answer down hope this helps
10) V=πr² *h= π*10²*12≈3770
11) V=A(base)*h= (3√3/2)*(9²)*10=2104
A(base)=(P*a)/2=(6*9*3√3)/2=9*9*3√3/2
12)V=πr² *h=π*18² *6≈6107
13)V=4*3*12=144
14) h(triangle)=√(5²-3²)=√16=4
A(base)=(3*4)/2=6
V=A(base)* height (prism)=6*2=12
15) V=A(base)*h= (3√3/2)*(6²)*11= 1029
16)V=A(base)*h=2(1+√2)5²*22≈2656