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Alenkinab [10]
2 years ago
14

Log20x=3 need the answer for algebra 2

Mathematics
1 answer:
mel-nik [20]2 years ago
7 0

Answer:

x = 50

Step-by-step explanation:

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KonstantinChe [14]
The first question is probably around 12 cm. It looks to be about half of like AC. Then the third question would be a 90° angle I do belive
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Last geometry question!
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It reflected across line x = 3, y coordinate will remain the same. 

Answer: (7, 5)
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Find the value of X​
Aloiza [94]

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57

Step-by-step explanation:

7 0
4 years ago
Two staments that show the relationship between the values of the numbers 0.5 and 0.05
nirvana33 [79]
<span> The place value relationship of 0.5 and 0.05 in the given number
=> 0.5 and 0.05 are decimal numbers because they are place next to the decimal points.
=> 0.5 placed next to decimal point is tenths and 0.05 is in hundredths.
Now, what’s the relation of both numbers?
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=> How? Let’s try solving it
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</span>



4 0
4 years ago
Assume that the Poisson distribution applies to the number of births at a particular hospital during a randomly selected day. As
kakasveta [241]

Answer:

0.9999985  = 99.99985% probability that in a day, there will be at least 1 birth.

Step-by-step explanation:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

In which

x is the number of sucesses

e = 2.71828 is the Euler number

\mu is the mean in the given interval.

Assume that the mean number of births per day at this hospital is 13.4224.

This means that \mu = 13.4224

Find the probability that in a day, there will be at least 1 birth.

This is:

P(X \geq 1) = 1 - P(X = 0)

In which

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

P(X = 0) = \frac{e^{-13.4224}*13.4224^{0}}{(0)!} = 0.0000015

Then

P(X \geq 1) = 1 - P(X = 0) = 1 - 0.0000015 = 0.9999985&#10;

0.9999985  = 99.99985% probability that in a day, there will be at least 1 birth.

7 0
3 years ago
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