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Vesna [10]
2 years ago
15

Mr. endres wants to put fencing around his rectangular shaped backyard. the width of the backyard is 42 feet and the length is t

wo times the width. how many feet of fencing does mr. endres need?
Mathematics
1 answer:
Anna71 [15]2 years ago
7 0

The the number of feet needed for the fence of the rectangular garden = its perimeter = 252 ft.

<h3>What is the Perimeter of a Rectangle?</h3>

Perimeter = 2(length + width).

The number of feet needed for the fence around the rectangular garden = perimeter of teh rectangular garden.

Given the following:

  • Width = 42 ft.
  • Length = 2(42) = 84 ft.

Plug the values into Perimeter = 2(length + width):

Perimeter of the rectangular garden = 2(42 + 84)

Perimeter of the rectangular garden = 252 ft

Therefore, the the number of feet needed for the fence of the rectangular garden = its perimeter = 252 ft.

Learn more about perimeter of rectangle on:

brainly.com/question/24571594

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At the end of the day, a bakery gives everything that is unsold to food banks for the needy. If it has 12 apple pies left at the
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Answer:

462 ways

Step-by-step explanation:

The formula to use in solving this problem is given as the Combination formula

The Combination formula is given as

C(n , r) = nCr = n!/r! (n - r)!

We are told that a food bakery has 12 pies unsold at the end of the day which they intend to share to 6 food banks

n = 12, r = 6

In order to ensure that at least 1 food bank gets 1 pie, we have:

n - 1 = 12 - 1 = 11

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C(11, 5) = 11C5

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Biologists are studying tropical plants to determine how far north each type of plant can survive. What is the population?
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A football is thrown from the top of the stands, 50 feet above the ground at an initial velocity of 62 ft/sec and at an angle of
Anvisha [2.4K]

a. i. The parametric equation for the horizontal movement is x = 43.84t

ii. The parametric equation for the vertical movement is y = 50 + 43.84t

b. the location of the football at its maximum height relative to the starting point is (60.1 ft, 60.1 ft)

<h2>a. Parametric equations</h2>

A parametric equation is an equation that defines a set of quantities a functions of one or more independent variables called parameters.

<h3>i. Parametric equation for the horizontal movement</h3>

The parametric equation for the horizontal movement is x = 43.84t

Since

  • the angle of elevation is Ф = 45° and
  • the initial velocity, v = 62 ft/s,

the horizontal component of the velocity is v' = vcosФ.

So, the horizontal distance the football moves in time, t is x = vcosФt

= vtcosФ

= 62tcos45°

= 62t × 0.7071

= 43.84t

So, the parametric equation for the horizontal movement is x = 43.84t

<h3>ii Parametric equation for the vertical movement</h3>

The parametric equation for the vertical movement is y = 50 + 43.84t

Also, since

  • the angle of elevation is Ф = 45° and
  • the initial velocity, v = 62 ft/s,

the vertical component of the velocity is v" = vsinФ.

Since the football is initially at a height of h = 50 feet, the vertical distance the football moves in time, t relative to the ground is y = 50 + vsinФt

= 50 + vtcosФ

= 50 + 62tsin45°

= 50 + 62t × 0.7071

= 50 + 43.84t

<h3>b. Location of football at maximum height relative to starting point</h3>

The location of the football at its maximum height relative to the starting point is (60.1 ft, 60.1 ft)

Since the football reaches maximum height at t = 1.37 s

The x coordinate of its location at maximum height is gotten by substituting t = 1.37 into x = 48.84t

So, x = 43.84t

x = 43.84 × 1.37

x = 60.0608

x ≅ 60.1 ft

The y coordinate of the football's location at maximum height relative to the ground is y = 50 + 48.84t

The y coordinate of the football's location at maximum height relative to the starting point is y - 50 = 48.84t

So,  y - 50 = 48.84t

y - 50 = 43.84 × 1.37

y - 50 = 60.0608

y - 50 ≅ 60.1 ft

So, the location of the football at its maximum height relative to the starting point is (60.1 ft, 60.1 ft)

Learn ore about parametric equations here:

brainly.com/question/8674159

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